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Multiple Choice
Which of the following statements correctly describes the Lewis dot structure of the neutral compound P2H4?
A
Each phosphorus atom is bonded to four hydrogen atoms and has no bond to the other phosphorus atom.
B
Each phosphorus atom is bonded to three hydrogen atoms and to the other phosphorus atom by a double bond.
C
Each phosphorus atom is bonded to two hydrogen atoms and to the other phosphorus atom by a single bond.
D
Each phosphorus atom is bonded to one hydrogen atom and to the other phosphorus atom by a triple bond.
Verified step by step guidance
1
Step 1: Determine the total number of valence electrons available for the molecule P2H4. Phosphorus (P) has 5 valence electrons, and hydrogen (H) has 1 valence electron each. Calculate the total by adding the valence electrons from both phosphorus atoms and all four hydrogen atoms.
Step 2: Consider the bonding preferences of phosphorus and hydrogen. Hydrogen forms only one single bond, while phosphorus can form multiple bonds but typically prefers to form three bonds and may have a lone pair.
Step 3: Propose a skeletal structure where the two phosphorus atoms are bonded together, and the hydrogen atoms are distributed around the phosphorus atoms. Since there are four hydrogens, try assigning two hydrogens to each phosphorus atom.
Step 4: Assign electrons to form bonds between atoms, ensuring each hydrogen has a single bond and each phosphorus atom satisfies the octet rule as much as possible. Check if the phosphorus atoms are connected by a single bond or multiple bonds by counting the electrons used.
Step 5: Verify the Lewis structure by counting all valence electrons used in bonds and lone pairs to ensure the total matches the number calculated in Step 1, confirming the correct bonding arrangement.