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Multiple Choice
Which of the following shows the correct Lewis valence dot structure for a neutral oxygen atom?
A
O with two dots placed on opposite sides of the symbol
B
O with eight dots arranged as four pairs around the symbol
C
O with four dots arranged as two pairs around the symbol
D
O with six dots arranged as two pairs and two single dots around the symbol
Verified step by step guidance
1
Recall that the Lewis valence dot structure represents the valence electrons of an atom as dots placed around the chemical symbol.
Determine the number of valence electrons for oxygen. Oxygen is in group 16 of the periodic table, so it has 6 valence electrons.
Distribute these 6 valence electrons as dots around the symbol 'O'. According to Lewis structure conventions, place one dot on each side before pairing them, to represent unpaired electrons first.
Arrange the 6 dots as two pairs (each pair representing two electrons) and two single dots on different sides of the oxygen symbol, reflecting the total 6 valence electrons.
Verify that the structure shows all 6 valence electrons without exceeding the octet rule for oxygen, ensuring the atom remains neutral.