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Multiple Choice
Which of the following best describes the electron domain geometry and molecular geometry of PH3 (phosphine) based on its Lewis dot structure?
A
Electron domain geometry: trigonal planar; Molecular geometry: bent
B
Electron domain geometry: tetrahedral; Molecular geometry: tetrahedral
C
Electron domain geometry: tetrahedral; Molecular geometry: trigonal pyramidal
D
Electron domain geometry: trigonal planar; Molecular geometry: trigonal planar
Verified step by step guidance
1
Draw the Lewis dot structure of PH\_3 by first counting the total valence electrons: phosphorus (P) has 5 valence electrons and each hydrogen (H) has 1, so total electrons = 5 + 3(1) = 8 electrons.
Arrange the atoms with phosphorus as the central atom bonded to three hydrogen atoms, and then distribute the remaining electrons to satisfy the octet rule for phosphorus, placing any leftover electrons as lone pairs on phosphorus.
Determine the electron domain geometry by counting the regions of electron density (bonding pairs + lone pairs) around the central phosphorus atom. Each bond and lone pair counts as one electron domain.
Identify the molecular geometry by considering only the positions of the atoms (bonding pairs) and ignoring the lone pairs. Lone pairs affect the shape by repelling bonding pairs, altering the molecular geometry from the electron domain geometry.
Conclude that with three bonding pairs and one lone pair on phosphorus, the electron domain geometry is tetrahedral (4 regions of electron density), and the molecular geometry is trigonal pyramidal (shape formed by the three bonded hydrogens and the lone pair).