Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

11. Bonding & Molecular Structure

Lewis Dot Structures: Neutral Compounds

General Chemistry

11. Bonding & Molecular Structure

Lewis Dot Structures: Neutral Compounds

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Multiple Choice

Which of the following statements correctly describes the Lewis dot structure of the neutral compound NBr3?

Nitrogen is at the center with three single bonds to bromine atoms and one lone pair on nitrogen.

Nitrogen is at the center with three single bonds to bromine atoms and no lone pairs on nitrogen.

Nitrogen is at the center with three double bonds to bromine atoms and no lone pairs on nitrogen.

Bromine is at the center with three single bonds to nitrogen atoms and one lone pair on bromine.

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Verified step by step guidance

Step 1: Identify the central atom in NBr3. Generally, the less electronegative atom is placed at the center. Between nitrogen (N) and bromine (Br), nitrogen is less electronegative, so nitrogen will be the central atom.

Step 2: Determine the total number of valence electrons. Nitrogen has 5 valence electrons, and each bromine has 7 valence electrons. Since there are three bromine atoms, total valence electrons = 5 + 3 × 7 = 26 electrons.

Step 3: Draw single bonds between the central nitrogen atom and each bromine atom. Each single bond uses 2 electrons, so 3 bonds use 6 electrons, leaving 20 electrons to be distributed as lone pairs.

Step 4: Complete the octets of the bromine atoms by placing lone pairs around each bromine. Each bromine needs 6 more electrons (3 lone pairs) to complete its octet, using 18 electrons in total.

Step 5: Place the remaining electrons on the nitrogen atom as lone pairs. After bonding and completing bromine octets, nitrogen will have one lone pair to complete its octet, resulting in nitrogen bonded to three bromines with one lone pair on nitrogen.