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Multiple Choice
Which one of the following substances would be the most soluble in CCl_4?
A
I_2 (iodine)
B
KNO_3 (potassium nitrate)
C
NaCl (sodium chloride)
D
NH_3 (ammonia)
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Verified step by step guidance
1
Step 1: Understand the principle of solubility 'like dissolves like,' which means that polar solvents tend to dissolve polar solutes, and nonpolar solvents tend to dissolve nonpolar solutes.
Step 2: Identify the polarity of the solvent CCl\_4 (carbon tetrachloride). CCl\_4 is a nonpolar molecule because of its symmetrical tetrahedral shape and the similar electronegativities of carbon and chlorine atoms.
Step 3: Analyze the polarity of each solute: KNO\_3 and NaCl are ionic compounds (highly polar), NH\_3 (ammonia) is a polar molecule due to its lone pair and molecular geometry, and I\_2 (iodine) is a nonpolar molecule because it consists of two identical atoms sharing electrons equally.
Step 4: Compare the solutes with the solvent polarity: since CCl\_4 is nonpolar, it will dissolve nonpolar substances better than polar or ionic substances.
Step 5: Conclude that I\_2 (iodine), being nonpolar, is the most soluble in CCl\_4 compared to the polar or ionic substances listed.