Join thousands of students who trust us to help them ace their exams!
Multiple Choice
Based on the solubility rules, which of the following compounds is most likely to be insoluble in water?
A
NH_4Br
B
NaNO_3
C
K_2SO_4
D
AgCl
0 Comments
Verified step by step guidance
1
Review the common solubility rules for ionic compounds in water, focusing on the solubility of ammonium (NH_4^+), alkali metal ions (such as Na^+ and K^+), and common anions like bromide (Br^-), nitrate (NO_3^-), and sulfate (SO_4^{2-}).
Recall that compounds containing ammonium (NH_4^+) and alkali metal ions (Na^+, K^+) are generally soluble in water regardless of the anion they are paired with.
Note that bromides (Br^-), nitrates (NO_3^-), and sulfates (SO_4^{2-}) are typically soluble, with some exceptions mainly for sulfates with heavy metals, but not for alkali metals or ammonium.
Understand that silver chloride (AgCl) is a classic example of an insoluble salt because silver (Ag^+) halides (except AgF) are generally insoluble in water according to solubility rules.
Conclude that among the given compounds, NH_4Br, NaNO_3, and K_2SO_4 are all soluble, while AgCl is the one most likely to be insoluble in water.