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Multiple Choice
In a water molecule (H_2O), what is the arrangement of all electron pairs (bonding and lone pairs) around the central oxygen atom?
A
Linear
B
Bent
C
Tetrahedral
D
Trigonal planar
Verified step by step guidance
1
Identify the central atom in the water molecule, which is oxygen (O).
Determine the number of valence electrons around the oxygen atom. Oxygen has 6 valence electrons.
Count the bonding pairs: oxygen forms two single bonds with two hydrogen atoms, so there are 2 bonding pairs.
Count the lone pairs: subtract the bonding electrons (2 bonds × 2 electrons each = 4 electrons) from the total valence electrons (6), leaving 2 electrons or 1 lone pair. Actually, oxygen has 2 lone pairs, so total electron pairs are 4 (2 bonding + 2 lone pairs).
Use the VSEPR theory to predict the arrangement of electron pairs around oxygen. Four electron pairs arrange themselves in a tetrahedral geometry to minimize repulsion, even though the molecular shape (based on atoms only) is bent.