Multiple Choice
In the Lewis dot structure of a neutral O_2 molecule, how many electrons are involved in bonding between the two oxygen atoms?
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11. Bonding & Molecular Structure
Lewis Dot Structures: Neutral Compounds
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
How many lone pairs of electrons are present in the Lewis dot structure of ammonia (NH_3)?
A
3
B
0
C
1
D
2
Verified step by step guidance1
Identify the total number of valence electrons for each atom in ammonia (NH_3). Nitrogen (N) has 5 valence electrons, and each hydrogen (H) has 1 valence electron.
Calculate the total valence electrons in the molecule by adding the valence electrons of nitrogen and the three hydrogens: $5 + 3 \times 1$.
Draw the Lewis structure by placing nitrogen in the center and connecting each hydrogen atom to nitrogen with a single bond, which accounts for 2 electrons per bond.
Subtract the electrons used in bonding from the total valence electrons to find the remaining electrons, which will be placed as lone pairs on nitrogen.
Determine the number of lone pairs on nitrogen by dividing the remaining electrons by 2 (since each lone pair consists of 2 electrons).
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