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Multiple Choice
How many electrons are present in an Al^{3+} ion?
A
13
B
10
C
16
D
3
Verified step by step guidance
1
Identify the atomic number of aluminum (Al), which is 13. This number represents the number of protons and, in a neutral atom, also the number of electrons.
Understand that the Al^{3+} ion has lost 3 electrons compared to the neutral atom because of the 3+ charge.
Calculate the number of electrons in the Al^{3+} ion by subtracting the charge (3) from the number of electrons in the neutral atom (13): $13 - 3$.
Write the expression for the number of electrons in the ion: $\text{electrons in Al}^{3+} = 13 - 3$.
Conclude that the Al^{3+} ion has fewer electrons than the neutral atom due to the positive charge.