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Multiple Choice
How many electrons are present in an Al^{3+} ion?
A
13
B
10
C
3
D
16
Verified step by step guidance
1
Identify the atomic number of aluminum (Al), which is 13. This number represents the number of protons and, in a neutral atom, also the number of electrons.
Understand that the charge on the ion, Al^{3+}, indicates it has lost 3 electrons compared to the neutral atom.
Calculate the number of electrons in the Al^{3+} ion by subtracting the charge (3) from the number of electrons in the neutral atom (13): $13 - 3$.
Express the calculation as $\text{Number of electrons} = 13 - 3$ to find the total electrons in the ion.
Conclude that the Al^{3+} ion has fewer electrons than the neutral atom due to the positive charge, resulting in the final count of electrons.