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Multiple Choice
What is the average oxidation number of sulfur in sodium thiosulfate, ?
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Identify the chemical formula of sodium thiosulfate: \(\mathrm{Na_2S_2O_3}\).
Assign known oxidation numbers: sodium (Na) is always +1, and oxygen (O) is usually -2.
Set up an equation for the sum of oxidation numbers in the compound, which must equal zero because the compound is neutral: \$2(\text{oxidation of Na}) + 2(\text{oxidation of S}) + 3(\text{oxidation of O}) = 0$.
Substitute the known values: \$2(+1) + 2(x) + 3(-2) = 0\(, where \)x$ is the average oxidation number of sulfur.
Solve the equation for \(x\) to find the average oxidation number of sulfur in sodium thiosulfate.