Multiple Choice
Which of the following electron configurations correctly represents the electron density of aluminum (Al, atomic number 13)?
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10. Periodic Properties of the Elements
The Electron Configuration
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Which of the following is the correct electron configuration for the Ti^{2+} ion?
A
[Ar] 4s^2 3d^2
B
[Ar] 4s^2 3d^0
C
[Ar] 3d^2
D
[Ar] 3d^4
Verified step by step guidance1
Step 1: Identify the atomic number of titanium (Ti), which is 22. This means a neutral Ti atom has 22 electrons.
Step 2: Write the electron configuration for the neutral Ti atom. The order of filling is 1s, 2s, 2p, 3s, 3p, 4s, then 3d. So, Ti's configuration is $[Ar] 4s^2 3d^2$.
Step 3: Understand that when forming a $Ti^{2+}$ ion, two electrons are removed. Electrons are removed first from the outermost shell, which is the 4s orbital before the 3d orbital.
Step 4: Remove the two electrons from the 4s orbital of the neutral Ti configuration, resulting in $[Ar] 3d^2$ for the $Ti^{2+}$ ion.
Step 5: Confirm that the correct electron configuration for $Ti^{2+}$ is $[Ar] 3d^2$, which matches the removal of electrons from the 4s orbital first.
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