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Multiple Choice
Which of the following electron configurations correctly represents the electron density of aluminum (Al, atomic number 13)?
A
1s^2 2s^2 2p^6 3s^2 3p^3
B
1s^2 2s^2 2p^6 3s^2 3p^2
C
1s^2 2s^2 2p^6 3s^1 3p^2
D
1s^2 2s^2 2p^6 3s^2 3p^1
Verified step by step guidance
1
Step 1: Identify the atomic number of aluminum (Al), which is 13. This means aluminum has 13 electrons to be arranged in its electron configuration.
Step 2: Recall the order in which electron orbitals are filled according to the Aufbau principle: 1s, 2s, 2p, 3s, 3p, and so on.
Step 3: Fill the orbitals with electrons following the maximum capacity of each orbital: 1s can hold 2 electrons, 2s can hold 2, 2p can hold 6, 3s can hold 2, and 3p can hold 6.
Step 4: Distribute the 13 electrons accordingly: fill 1s with 2 electrons, 2s with 2 electrons, 2p with 6 electrons, 3s with 2 electrons, and place the remaining 1 electron in the 3p orbital.
Step 5: Write the electron configuration based on this distribution: $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{1}$, which correctly represents the electron density of aluminum.