Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

3. Chemical Reactions

Naming Ionic Compounds

General Chemistry

3. Chemical Reactions

Naming Ionic Compounds

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Multiple Choice

Which of the following is the correct chemical formula for aluminum chromate?

AlCrO4

Al(CrO4)2

Al2CrO4

Al2(CrO4)3

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Verified step by step guidance

Step 1: Identify the ions involved and their charges. Aluminum typically forms a cation with a charge of +3, written as Al^{3+}. The chromate ion is a polyatomic anion with the formula CrO_4^{2-}, carrying a charge of -2.

Step 2: Determine the ratio of aluminum ions to chromate ions needed to balance the overall charge of the compound. Since aluminum has a +3 charge and chromate has a -2 charge, find the least common multiple (LCM) of the charges to balance them.

Step 3: Calculate the number of each ion required to achieve charge neutrality. The LCM of 3 and 2 is 6, so you need enough Al^{3+} ions to provide a total positive charge of +6 and enough CrO_4^{2-} ions to provide a total negative charge of -6.

Step 4: Determine the subscripts for each ion based on the charge balance. To get +6 from Al^{3+}, you need 2 aluminum ions (2 × +3 = +6). To get -6 from CrO_4^{2-}, you need 3 chromate ions (3 × -2 = -6).

Step 5: Write the chemical formula by placing the number of each ion as subscripts, using parentheses for the polyatomic ion if there is more than one. The correct formula is Al_2(CrO_4)_3.