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Multiple Choice
For the ion Fe^{2+}, how many electrons are present in its valence d orbitals?
A
5
B
2
C
4
D
6
Verified step by step guidance
1
Identify the atomic number of iron (Fe), which is 26. This means a neutral Fe atom has 26 electrons.
Determine the electron configuration of neutral Fe: $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^6$.
Recognize that Fe^{2+} means the iron ion has lost 2 electrons. Electrons are removed first from the outermost shell, which is the 4s orbital in this case.
Remove 2 electrons from the 4s orbital, leaving the electron configuration for Fe^{2+} as $1s^2 2s^2 2p^6 3s^2 3p^6 3d^6$.
Count the number of electrons in the 3d orbitals for Fe^{2+}, which is 6 electrons.