Join thousands of students who trust us to help them ace their exams!
Multiple Choice
Which of the following statements correctly describes the Lewis dot structure of the bromate ion, BrO_3^-?
A
BrO_3^- has two single bonds and one triple bond between Br and the O atoms, with the negative charge on bromine.
B
BrO_3^- has three double bonds between Br and each O atom, with no formal charges on any atom.
C
BrO_3^- has three single bonds between Br and each O atom, with one oxygen atom carrying a negative formal charge.
D
BrO_3^- has three single bonds between Br and each O atom, with the negative charge on bromine.
0 Comments
Verified step by step guidance
1
Step 1: Determine the total number of valence electrons available for the BrO_3^- ion. Bromine (Br) has 7 valence electrons, each oxygen (O) has 6 valence electrons, and there is an extra electron due to the negative charge. So, total valence electrons = 7 + 3 × 6 + 1.
Step 2: Draw a skeletal structure with bromine as the central atom bonded to three oxygen atoms. Connect each oxygen to bromine with a single bond initially.
Step 3: Distribute the remaining valence electrons to satisfy the octet rule for oxygen atoms first, placing lone pairs on oxygens to complete their octets.
Step 4: Check the formal charges on each atom using the formula: \(\text{Formal charge} = \text{Valence electrons} - \text{Nonbonding electrons} - \frac{1}{2} \times \text{Bonding electrons}\). Adjust bonding (single, double, or triple bonds) if necessary to minimize formal charges and place the negative charge on the most electronegative atom (oxygen).
Step 5: Confirm that the final Lewis structure has bromine bonded to three oxygens with single bonds, one oxygen carrying the negative charge (formal charge of -1), and all atoms having formal charges as close to zero as possible, consistent with the known structure of BrO_3^-.