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Multiple Choice
Which of the following statements correctly describes the Lewis dot structure of the ion IF_2^-?
A
The central iodine atom has three lone pairs and forms two single bonds with fluorine atoms.
B
The central iodine atom has no lone pairs and forms two single bonds with fluorine atoms, resulting in a bent molecular geometry.
C
The central iodine atom has two lone pairs and forms two single bonds with fluorine atoms, resulting in a linear molecular geometry.
D
The central iodine atom has one lone pair and forms two double bonds with fluorine atoms.
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Verified step by step guidance
1
Step 1: Determine the total number of valence electrons for the IF_2^- ion. Iodine (I) has 7 valence electrons, each fluorine (F) has 7 valence electrons, and the negative charge adds 1 extra electron. So, total valence electrons = 7 (I) + 2 × 7 (F) + 1 (charge).
Step 2: Draw the skeletal structure with iodine as the central atom bonded to two fluorine atoms. Connect iodine to each fluorine with a single bond, which uses 2 electrons per bond.
Step 3: Distribute the remaining valence electrons to complete the octets of the fluorine atoms first, since fluorine is more electronegative and typically completes its octet with lone pairs.
Step 4: Assign the leftover electrons to the central iodine atom as lone pairs. Count how many lone pairs iodine has after bonding and electron distribution.
Step 5: Use the VSEPR theory to determine the molecular geometry based on the number of bonding pairs and lone pairs on iodine. Two bonding pairs and two lone pairs on iodine correspond to a linear molecular geometry for IF_2^-.