Join thousands of students who trust us to help them ace their exams!Watch the first video
Multiple Choice
In the reaction between Pb(NO3)2 and MgSO4 in aqueous solution, which product forms a precipitate?
A
MgCl2
B
PbMg
C
PbSO4
D
No precipitate formed
Verified step by step guidance
1
Identify the reactants and their ions in aqueous solution: Pb(NO3)2 dissociates into Pb^{2+} and NO_3^{-} ions, and MgSO_4 dissociates into Mg^{2+} and SO_4^{2-} ions.
Determine the possible products by exchanging the ions between the reactants: Pb^{2+} can pair with SO_4^{2-} to form PbSO_4, and Mg^{2+} can pair with NO_3^{-} to form Mg(NO_3)_2.
Check the solubility rules to see which product is insoluble and will form a precipitate. According to common solubility rules, most sulfates are soluble except those of Pb^{2+}, Ba^{2+}, and Ca^{2+}, so PbSO_4 is likely to be insoluble.
Confirm that Mg(NO_3)_2 is soluble in water, so it remains dissolved and does not form a precipitate.
Conclude that PbSO_4 is the precipitate formed in the reaction between Pb(NO_3)_2 and MgSO_4 in aqueous solution.