Join thousands of students who trust us to help them ace their exams!
Multiple Choice
In the reaction between Pb(NO3)2 and MgSO4 in aqueous solution, which product forms a precipitate?
A
MgCl2
B
PbMg
C
PbSO4
D
No precipitate formed
0 Comments
Verified step by step guidance
1
Identify the reactants and their ions in aqueous solution: Pb(NO3)2 dissociates into Pb^{2+} and NO_3^{-} ions, and MgSO_4 dissociates into Mg^{2+} and SO_4^{2-} ions.
Determine the possible products by exchanging the ions between the reactants: Pb^{2+} can pair with SO_4^{2-} to form PbSO_4, and Mg^{2+} can pair with NO_3^{-} to form Mg(NO_3)_2.
Check the solubility rules to see which product is insoluble and will form a precipitate. According to common solubility rules, most sulfates are soluble except those of Pb^{2+}, Ba^{2+}, and Ca^{2+}, so PbSO_4 is likely to be insoluble.
Confirm that Mg(NO_3)_2 is soluble in water, so it remains dissolved and does not form a precipitate.
Conclude that PbSO_4 is the precipitate formed in the reaction between Pb(NO_3)_2 and MgSO_4 in aqueous solution.