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Multiple Choice
At 100°C, the solubility of NaCl in water is approximately 39 g per 100 mL. How many grams of NaCl are required to prepare 600 mL of a saturated NaCl solution at 100°C?
A
234 g
B
117 g
C
39 g
D
600 g
Verified step by step guidance
1
Identify the given data: solubility of NaCl is 39 g per 100 mL of water at 100°C, and the volume of solution to prepare is 600 mL.
Set up a proportion to find the mass of NaCl needed for 600 mL based on the solubility given for 100 mL. The proportion is: $\frac{39\ \text{g}}{100\ \text{mL}} = \frac{x\ \text{g}}{600\ \text{mL}}$ where $x$ is the mass of NaCl required.
Solve the proportion for $x$ by cross-multiplying: $x = \frac{39 \times 600}{100}$.
Calculate the value of $x$ to find the grams of NaCl needed to saturate 600 mL of water at 100°C (do not provide the final numeric answer here).
Interpret the result as the amount of NaCl required to prepare a saturated solution of 600 mL at 100°C.