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Multiple Choice
A compound is found to have a molar mass of 598 g/mol. If 35.8 mg of the compound is dissolved in enough water to make 175 mL of solution at 25°C, what is the osmotic pressure of the resulting solution? (Assume ideal behavior and R = 0.0821 L·atm/mol·K)
A
0.0012 atm
B
0.012 atm
C
1.200 atm
D
0.120 atm
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1
Convert the mass of the compound from milligrams to grams by dividing by 1000. This is necessary because molar mass is given in grams per mole.
Calculate the number of moles of the compound using the formula: \( \text{moles} = \frac{\text{mass in grams}}{\text{molar mass}} \).
Determine the molarity of the solution by dividing the number of moles by the volume of the solution in liters. Convert the volume from milliliters to liters by dividing by 1000.
Use the formula for osmotic pressure: \( \Pi = MRT \), where \( M \) is the molarity, \( R \) is the ideal gas constant (0.0821 L·atm/mol·K), and \( T \) is the temperature in Kelvin. Convert the temperature from Celsius to Kelvin by adding 273.15.
Substitute the values for molarity, \( R \), and \( T \) into the osmotic pressure formula to calculate the osmotic pressure of the solution.