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Multiple Choice
Calculate the osmotic pressure of a solution containing 18.95 mg of hemoglobin in 16.6 mL of solution at 18 °C. The molar mass of hemoglobin is 6.5×10^4 g/mol. Express your answer in atmospheres.
A
0.0012 atm
B
0.012 atm
C
0.12 atm
D
1.2 atm
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Verified step by step guidance
1
First, convert the mass of hemoglobin from milligrams to grams. Since 1 mg = 0.001 g, multiply 18.95 mg by 0.001 to get the mass in grams.
Next, calculate the number of moles of hemoglobin using the formula: \( \text{moles} = \frac{\text{mass in grams}}{\text{molar mass}} \). Use the molar mass of hemoglobin, which is \( 6.5 \times 10^4 \text{ g/mol} \).
Convert the volume of the solution from milliliters to liters. Since 1 mL = 0.001 L, multiply 16.6 mL by 0.001 to get the volume in liters.
Use the formula for osmotic pressure: \( \Pi = \frac{n}{V}RT \), where \( n \) is the number of moles, \( V \) is the volume in liters, \( R \) is the ideal gas constant (0.0821 L·atm/mol·K), and \( T \) is the temperature in Kelvin. Convert the temperature from Celsius to Kelvin by adding 273.15 to 18 °C.
Substitute the values into the osmotic pressure formula and solve for \( \Pi \). This will give you the osmotic pressure in atmospheres.