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Multiple Choice
Determine the overall charge of the adduct when the aluminum ion combines with 2 bromides and 1 chlorides.
A
+1
B
0
C
–2
D
–1
E
+2
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1
Identify the charge of each ion involved in the formation of the adduct. Aluminum ion (Al) typically has a charge of +3, bromide ion (Br) has a charge of -1, and chloride ion (Cl) also has a charge of -1.
Write the chemical formula for the adduct formed by combining one aluminum ion with two bromide ions and one chloride ion. This can be represented as AlBr₂Cl.
Calculate the total positive charge contributed by the aluminum ion. Since aluminum has a charge of +3, the total positive charge is +3.
Calculate the total negative charge contributed by the bromide and chloride ions. With two bromide ions each having a charge of -1, the total negative charge from bromides is -2. The chloride ion contributes an additional -1 charge, making the total negative charge -3.
Determine the overall charge of the adduct by adding the total positive and negative charges. The sum of +3 (from aluminum) and -3 (from bromides and chloride) results in an overall charge of 0.