Multiple Choice
A 5.12 L sample of solution contains 0.230 g of potassium sulfate, K2SO4. Determine the concentration of K2SO4 in ppm if the density of the solution is 1.30 g/mL.
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14. Solutions
Parts per Million (ppm)
Multiple Choice
A water sample contains the pollutant chlorobenzene with a concentration of 16 ppm (by volume). What volume of this water contains 5.01×102 mL of chlorobenzene?
A
3.1 × 107 mL
B
3.2 × 104 mL
C
1.6 × 106 mL
D
8.0 × 1010 mL
Verified step by step guidance1
Understand that ppm (parts per million) by volume means that for every 1 million parts of the solution, there are 16 parts of chlorobenzene.
Set up a proportion to find the total volume of water that contains 5.01 × 10^2 mL of chlorobenzene. Use the relationship: (16 mL chlorobenzene / 1,000,000 mL water) = (5.01 × 10^2 mL chlorobenzene / X mL water).
Cross-multiply to solve for X, the total volume of water: 16 * X = 5.01 × 10^2 * 1,000,000.
Rearrange the equation to solve for X: X = (5.01 × 10^2 * 1,000,000) / 16.
Calculate the value of X to find the total volume of water that contains 5.01 × 10^2 mL of chlorobenzene.
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