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Multiple Choice
The heat of vaporization of liquid isopropyl alcohol is 159 cal/g. Calculate the energy required to vaporize 39.5 g of this compound.
A
3950 cal
B
6280.5 cal
C
790 cal
D
1590 cal
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Verified step by step guidance
1
Identify the given values: the heat of vaporization of isopropyl alcohol is 159 cal/g, and the mass of the alcohol to be vaporized is 39.5 g.
Understand the concept: The heat of vaporization is the amount of energy required to convert 1 gram of a liquid into a gas at constant temperature and pressure.
Set up the formula to calculate the energy required for vaporization: Energy (cal) = Heat of vaporization (cal/g) × Mass (g).
Substitute the given values into the formula: Energy = 159 cal/g × 39.5 g.
Perform the multiplication to find the total energy required to vaporize the given mass of isopropyl alcohol.