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Multiple Choice
The heat of vaporization of water at 100°C is 40.66 kJ/mol. Calculate the quantity of heat that is absorbed or released when 20.00 g of steam condenses to liquid water at 100°C.
A
45.20 kJ released
B
22.60 kJ absorbed
C
22.60 kJ released
D
45.20 kJ absorbed
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Verified step by step guidance
1
First, identify the process occurring: steam is condensing to liquid water at 100°C. This means heat is released during the condensation process.
Determine the molar mass of water (H₂O). The molar mass is calculated as follows: H (1.01 g/mol) * 2 + O (16.00 g/mol) = 18.02 g/mol.
Convert the mass of steam (20.00 g) to moles using the molar mass of water. Use the formula: \( \text{moles} = \frac{\text{mass}}{\text{molar mass}} \).
Calculate the quantity of heat released using the heat of vaporization. Use the formula: \( \text{heat} = \text{moles} \times \text{heat of vaporization} \).
Since the process is condensation, the heat calculated will be released. Ensure to express the final answer with the correct sign indicating heat release.