Using Raoult's Law, calculate the vapor pressure of water at 50.0°C if the pure vapor pressure of water at this temperature is 12.3 kPa and a non-volatile solute is added to form a solution with a mole fraction of water of 0.8.

Understand Raoult's Law: Raoult's Law states that the vapor pressure of a solvent in a solution is equal to the mole fraction of the solvent multiplied by the vapor pressure of the pure solvent. The formula is: $P=X{P}_0$, where $P$ is the vapor pressure of the solvent in the solution, $X$ is the mole fraction of the solvent, and $P_0$ is the vapor pressure of the pure solvent.