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Multiple Choice
How much energy is released when 65.8 g of water freezes, given that the enthalpy of fusion for water is 6.01 kJ/mol?
A
12.5 kJ
B
15.3 kJ
C
8.0 kJ
D
22.0 kJ
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Verified step by step guidance
1
First, understand that the enthalpy of fusion refers to the energy required to change a substance from solid to liquid at its melting point. When water freezes, the same amount of energy is released as it transitions from liquid to solid.
Next, convert the mass of water from grams to moles. Use the molar mass of water, which is approximately 18.02 g/mol. The formula to convert grams to moles is: \( \text{moles} = \frac{\text{mass in grams}}{\text{molar mass}} \).
Calculate the number of moles of water by substituting the given mass (65.8 g) and the molar mass of water (18.02 g/mol) into the formula: \( \text{moles} = \frac{65.8}{18.02} \).
Once you have the number of moles, use the enthalpy of fusion to find the energy released. The formula is: \( \text{Energy released} = \text{moles} \times \text{enthalpy of fusion} \).
Substitute the calculated moles and the given enthalpy of fusion (6.01 kJ/mol) into the formula: \( \text{Energy released} = \text{moles} \times 6.01 \). This will give you the energy released when 65.8 g of water freezes.