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Multiple Choice
Which of the following is the correct Lewis dot structure for the neutral compound HCP (hydrogen cyanophosphide)?
A
H–C=P with two lone pairs on phosphorus
B
H–C–P with three lone pairs on phosphorus
C
H=C=P with a lone pair on carbon
D
H–C≡P with a lone pair on phosphorus
Verified step by step guidance
1
Step 1: Determine the total number of valence electrons for the molecule HCP. Hydrogen (H) has 1 valence electron, carbon (C) has 4, and phosphorus (P) has 5. Add these together to get the total valence electrons available for bonding and lone pairs.
Step 2: Arrange the atoms in a reasonable skeletal structure. Since hydrogen typically forms only one bond, it will be bonded to carbon. Carbon and phosphorus will be connected to each other. So the skeleton is H–C–P.
Step 3: Use the total valence electrons to form bonds between atoms. Start by placing single bonds between H and C, and between C and P. Each single bond accounts for 2 electrons. Then distribute the remaining electrons to satisfy the octet rule for carbon and phosphorus, placing lone pairs as needed.
Step 4: Consider multiple bonds to satisfy the octet rule and minimize formal charges. Carbon and phosphorus can form double or triple bonds. Check the formal charges for each atom with different bonding arrangements to find the most stable structure. The correct structure will have minimal formal charges and satisfy the octet rule where possible.
Step 5: Confirm the final Lewis structure by verifying that the total number of electrons used equals the total valence electrons, that hydrogen has only one bond, and that carbon and phosphorus have appropriate bonds and lone pairs. The correct structure is H–C≡P with a lone pair on phosphorus.