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Multiple Choice
When 0.418 g of pentene, C5H12, is burned in a bomb calorimeter, the temperature rises by 4.21 °C. The heat capacity of the calorimeter is 2.46 kJ/°C. Calculate the combustion energy (ΔE) for pentene, C5H12, in kJ/g.
A
-10.3 kJ/g
B
-30.2 kJ/g
C
-24.7 kJ/g
D
-15.5 kJ/g
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1
Identify the given values: mass of pentene (C5H12) is 0.418 g, temperature change (ΔT) is 4.21 °C, and the heat capacity of the calorimeter (C_cal) is 2.46 kJ/°C.
Calculate the total heat absorbed by the calorimeter using the formula: q_cal = C_cal × ΔT. This will give you the heat absorbed in kJ.
Since the heat absorbed by the calorimeter is equal to the heat released by the combustion of pentene, the combustion energy (ΔE) can be calculated as: ΔE = -q_cal.
To find the combustion energy per gram of pentene, divide the total combustion energy (ΔE) by the mass of pentene: ΔE_per_gram = ΔE / mass of pentene.
Ensure the units are consistent and the final answer is expressed in kJ/g, which represents the energy change per gram of pentene burned.