Ch.3 - Chemical Reactions and Reaction Stoichiometry

Brown - Chemistry: The Central Science 14th Edition

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Brown 14th Edition

Ch.3 - Chemical Reactions and Reaction Stoichiometry

Problem 38d

Chapter 3, Problem 38d

(d) What is the molar mass of diazepam (Valium®) if 0.05570 mol has a mass of 15.86 g?

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Identify the formula for molar mass: \( \text{Molar Mass} = \frac{\text{Mass of the substance (g)}}{\text{Amount of substance (mol)}} \).

Substitute the given values into the formula: \( \text{Molar Mass} = \frac{15.86 \text{ g}}{0.05570 \text{ mol}} \).

Perform the division to find the molar mass in grams per mole (g/mol).

Ensure the units are correct: the result should be in g/mol, which is the standard unit for molar mass.

Review the calculation to ensure accuracy and consistency with the given data.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Molar Mass

Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). It is calculated by summing the atomic masses of all the atoms in a molecule. Understanding molar mass is essential for converting between the mass of a substance and the amount in moles, which is crucial for stoichiometric calculations in chemistry.

Moles

A mole is a unit in chemistry that represents a specific quantity of particles, typically atoms or molecules, equivalent to Avogadro's number, approximately 6.022 x 10²³. The concept of moles allows chemists to count and relate the mass of substances to the number of particles, facilitating calculations in chemical reactions and formulations.

Mass and Moles Relationship

The relationship between mass and moles is defined by the equation: mass = moles × molar mass. This equation allows for the conversion between the mass of a substance and the number of moles present. In the context of the question, knowing the mass of diazepam and the number of moles enables the calculation of its molar mass, which is a fundamental aspect of quantitative chemistry.

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Mass and Moles Conversion

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