calculate-h-s-and-g-at-25-0-c-for-the-following-reaction-2-al-s-6-hcl-g-2-alcl3-

Question

Calculate ΔH°, ΔS°, and ΔG° at 25.0°C for the following reaction: 2 Al(s) + 6 HCl(g) → 2 AlCl₃(s) + 3 H₂(g). Use the values given below:
          ΔH° (kJ/mol)     S° (J/mol•K)
Al(s)      0              28.32
AlCl₃(s)   –705.6        109.3
HCl(g)    –92.30         186.69
H₂(g)      0              130.58

Accepted Answer

ΔH° = –8.57×$$10^{2} kJ$$; ΔS° = –0.567 kJ/K; ΔG° = –6.88×$$10^{2} kJ$$

Answer

ΔH° = 8.57×$$10^{2} kJ$$; ΔS° = –0.567 kJ/K; ΔG° = –1.03×$$10^{3} kJ$$

Answer

ΔH° =– 8.57×$$10^{2} kJ$$; ΔS° = –0.567 kJ/K; ΔG° = +1.03×$$10^{3} kJ$$

Answer

ΔH° = 8.57×$$10^{2} kJ$$; ΔS° = 0.567 kJ/K; ΔG° = +6.88×$$10^{2} kJ$$