BackCHM 121 Exam 2 Study Guide: Chemical Reactions, Stoichiometry, and Reactions in Aqueous Solution
Study Guide - Smart Notes
Tailored notes based on your materials, expanded with key definitions, examples, and context.
Chapter 3: Chemical Reactions and Reaction Stoichiometry
Balancing Chemical Equations
Balancing chemical equations is essential to ensure the conservation of mass and atoms in a chemical reaction. Each side of the equation must have the same number of atoms for each element.
Key Point: Adjust coefficients (not subscripts) to balance atoms.
Key Point: Start with the most complex molecule and balance elements one at a time.
Example:
Calculating Moles from Mass
To convert grams of an element or compound to moles, use the molar mass as a conversion factor.
Key Point: Molar mass is the mass (in grams) of one mole of a substance.
Formula:
Example: 18 g of water () is mole.
Calculating Atoms or Molecules from Moles
Avogadro’s number () is used to convert between moles and the number of particles (atoms or molecules).
Key Point: 1 mole contains particles.
Formula:
Example: 2 moles of atoms contain atoms.
Empirical Formula Determination
The empirical formula represents the simplest whole-number ratio of elements in a compound. It is determined from the mass composition of each element.
Key Point: Convert mass to moles for each element, then divide by the smallest number of moles.
Example: If a compound contains 40 g C and 6.7 g H:
C: mol
H: mol
Ratio: C:H = 1:2 → Empirical formula
Molecular Formula Determination
The molecular formula shows the actual number of atoms in a molecule. It is found by comparing the empirical formula mass to the molar mass.
Key Point:
Formula: Multiply the empirical formula by n to get the molecular formula.
Example: Empirical formula , molar mass 28 g/mol. Empirical mass = 14 g/mol, so n = 2. Molecular formula = .
Stoichiometric Calculations
Stoichiometry involves quantitative relationships between reactants and products in a chemical reaction.
Key Point: Use balanced equations to relate moles of substances.
Steps:
Convert mass to moles.
Use mole ratios from the balanced equation.
Convert moles back to mass if needed.
Example: : 4 mol produces 4 mol .
Chapter 4: Reactions in Aqueous Solution
Electrolytes: Strong, Weak, and Non-Electrolytes
Electrolytes are substances that produce ions in solution and conduct electricity. They are classified based on their ionization in water.
Strong Electrolytes: Completely dissociate into ions (e.g., NaCl, HCl).
Weak Electrolytes: Partially dissociate (e.g., acetic acid, ammonia).
Non-Electrolytes: Do not produce ions (e.g., sugar, ethanol).
Example: NaCl in water is a strong electrolyte; CH3COOH is a weak electrolyte.
Precipitation Reactions and Ionic Equations
Precipitation reactions occur when two solutions mix and form an insoluble product (precipitate). Equations can be written in three forms.
Molecular Equation: Shows compounds as intact molecules.
Complete Ionic Equation: Shows all strong electrolytes as ions.
Net Ionic Equation: Shows only the ions and molecules directly involved in the reaction.
Example:
Molecular:
Complete Ionic:
Net Ionic:
Solubility Rules: Used to predict if a precipitate will form. (Will be provided during the exam.)
Acid-Base Neutralization Reactions
Strong acid and strong base neutralization reactions produce water and a salt. Equations can be written in molecular, complete ionic, and net ionic forms.
Example:
Molecular:
Complete Ionic:
Net Ionic:
Oxidation-Reduction (Redox) Reactions and Oxidation Numbers
Redox reactions involve the transfer of electrons. Oxidation numbers help track electron movement.
Key Point: Oxidation is loss of electrons; reduction is gain of electrons.
Rules for Assigning Oxidation Numbers:
Elemental form: 0
Monatomic ion: charge of ion
Oxygen: usually -2
Hydrogen: +1 (except in metal hydrides: -1)
Fluorine: always -1
Sum of oxidation numbers equals charge of molecule/ion
Example: In , H is +1, O is -2.
Calculating Molarity of Solutions
Molarity (M) is a measure of concentration, defined as moles of solute per liter of solution.
Formula:
Example: 0.5 moles NaCl in 1.0 L solution:
Exam Format and Allowed Materials
Short Answer and Calculation Problems: Show all work for calculations.
Closed Book, No Notes: Only a Periodic Table will be provided.
Calculator: Stand-alone scientific calculator allowed; no phones or other electronics.