BackGeneral Chemistry: Reaction Rates, Rate Laws, and Arrhenius Equation Guidance
Study Guide - Practice Questions
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- #1 Multiple ChoiceFor the reaction $\mathrm{N_2 + 3H_2 \rightarrow 2NH_3}$, if the average rate of consumption of $\mathrm{H_2}$ is $0.0277\ \mathrm{M/s}$, what is the average rate of production of $\mathrm{NH_3}$?
- #2 Multiple ChoiceGiven the reaction $2\mathrm{H_2} + 2\mathrm{NO} \rightarrow \mathrm{N_2} + 2\mathrm{H_2O}$ with the rate law $\text{rate} = k[\mathrm{H_2}]^2[\mathrm{NO}]$, calculate the rate (in $\mathrm{M/s}$) if $k = 6.0 \times 10^4\ \mathrm{M^{-2}s^{-2}}$, $[\mathrm{H_2}] = 0.0010\ \mathrm{M}$, and $[\mathrm{NO}] = 0.0020\ \mathrm{M}$.
- #3 Multiple ChoiceUsing the following kinetic data for the reaction $2\mathrm{H_2} + 2\mathrm{NO} \rightarrow \mathrm{N_2} + 2\mathrm{H_2O}$: Exp 1: $[\mathrm{NO}] = 0.0050\ \mathrm{M}$, $[\mathrm{H_2}] = 0.0025\ \mathrm{M}$, rate $= 3.0 \times 10^{-3}\ \mathrm{M/s}$ Exp 2: $[\mathrm{NO}] = 0.0100\ \mathrm{M}$, $[\mathrm{H_2}] = 0.0025\ \mathrm{M}$, rate $= 6.0 \times 10^{-3}\ \mathrm{M/s}$ Exp 3: $[\mathrm{NO}] = 0.0050\ \mathrm{M}$, $[\mathrm{H_2}] = 0.0050\ \mathrm{M}$, rate $= 6.0 \times 10^{-3}\ \mathrm{M/s}$ Exp 4: $[\mathrm{NO}] = 0.0100\ \mathrm{M}$, $[\mathrm{H_2}] = 0.0050\ \mathrm{M}$, rate $= 1.2 \times 10^{-2}\ \mathrm{M/s}$ What is the correct rate law for this reaction?
Study Guide - Flashcards
Boost memory and lock in key concepts with flashcards created from your notes.
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- Rate Law Calculations6 Questions
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