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Stoichiometry and Chemical Quantities: Study Notes

Study Guide - Smart Notes

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Stoichiometry: Chemical Quantities and Calculations

Introduction to Stoichiometry

Stoichiometry is the branch of chemistry that deals with the quantitative relationships between reactants and products in a chemical reaction. It allows chemists to predict the amounts of substances consumed and produced in a given reaction.

  • Stoichiometric calculations are based on balanced chemical equations.

  • Key concepts include mole, molar mass, Avogadro's number, and percent composition.

  • Stoichiometry is essential for laboratory work, industrial processes, and understanding chemical reactions.

Molecular and Formula Weights

The molecular weight (or molar mass) of a compound is the sum of the atomic masses of all atoms in its chemical formula.

  • Molecular weight is measured in atomic mass units (amu) or grams per mole (g/mol).

  • To calculate, add the atomic masses of each element multiplied by the number of atoms present.

  • Formula weight applies to ionic compounds, while molecular weight applies to covalent compounds.

Example: The formula weight of NaCl is calculated as: Percent composition calculation example

Percent Composition

Percent composition expresses the mass percentage of each element in a compound.

  • Formula:

  • Used to determine the empirical formula and analyze purity.

Example: For :

  • Calculate mass of each element in 1 mol.

  • Divide by total molar mass and multiply by 100%.

The Mole Concept and Avogadro's Number

A mole is a unit that represents particles (atoms, molecules, ions).

  • Avogadro's number is .

  • 1 mole of any substance contains Avogadro's number of particles.

  • Used to convert between mass, moles, and number of particles.

Example: mol of Cu contains: atoms of Cu Mole and Avogadro's number calculation

Stoichiometric Calculations: Mole-to-Mole and Mass-to-Mass

Stoichiometric calculations use balanced equations to relate moles and masses of reactants and products.

  • Steps: (1) Write balanced equation, (2) Convert mass to moles, (3) Use mole ratio, (4) Convert moles to mass.

  • Mole ratios are derived from coefficients in the balanced equation.

Example: For :

  • Given mass of NaO$_2$, calculate moles.

  • Use mole ratio to find moles of O produced.

  • Convert moles of O to grams.

Stoichiometric calculation for oxygen production

Limiting Reactant and Theoretical Yield

The limiting reactant is the substance that is completely consumed first, limiting the amount of product formed.

  • Identify limiting reactant by comparing mole ratios.

  • Theoretical yield is the maximum amount of product possible.

  • Actual yield is often less due to losses; percent yield is calculated as:

Example: If 20 g of SO is produced from a reaction with a theoretical yield of 28.04 g: Percent yield calculation example

Worked Examples and Practice Problems

  • Calculating number of atoms in a given mass.

  • Finding mass of product from a given mass of reactant.

  • Determining limiting reactant and percent yield.

Example: How many moles of oxygen are in 0.12 mol of Al(NO)$_3$?

  • Each mole of Al(NO)$_3$ contains 9 moles of O.

  • mol O

Mole calculation for oxygen in Al(NO3)3

Summary Table: Key Stoichiometric Relationships

Concept

Formula

Example

Mole to Mass

2 mol HO × 18.02 g/mol = 36.04 g

Mass to Mole

36.04 g HO ÷ 18.02 g/mol = 2 mol

Mole to Particles

1 mol Na = atoms

Percent Composition

H in HO:

Percent Yield

20 g / 28.04 g × 100% = 71.4%

Additional info:

  • Some equations and examples were inferred for clarity and completeness.

  • Images included only where they directly reinforce calculations or concepts.

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