Predict a likely mode of decay for each unstable nuclide. c. Fr-202

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Step 1: Identify the atomic number of the nuclide. Francium (Fr) has an atomic number of 87.

Step 2: Compare the atomic number to the 'band of stability'. The band of stability is a region where stable nuclides exist. Nuclides with atomic numbers less than 83 undergo alpha decay or beta decay to reach the band of stability. Nuclides with atomic numbers greater than 83 usually undergo alpha decay.

Step 3: Since Francium (Fr) has an atomic number greater than 83, it is likely to undergo alpha decay.

Step 4: In alpha decay, the unstable nuclide loses an alpha particle, which is equivalent to a helium nucleus (2 protons and 2 neutrons).

Step 5: The atomic number decreases by 2 and the mass number decreases by 4 in alpha decay. So, the new nuclide after the decay of Fr-202 would have an atomic number of 85 and a mass number of 198.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Nuclear Decay

Nuclear decay is the process by which an unstable atomic nucleus loses energy by emitting radiation. This can occur through various modes, including alpha decay, beta decay, and gamma decay, each involving the release of different particles or energy forms. Understanding the type of decay helps predict the resulting nuclide and its stability.

Beta Decay

Beta decay involves the transformation of a neutron into a proton (or vice versa) within the nucleus, accompanied by the emission of a beta particle (an electron or positron). This process changes the atomic number of the nuclide, leading to the formation of a different element. It is common in nuclides that are neutron-rich or proton-rich, respectively.

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