The nuclear DNA content of a single sperm cell in Drosophi...

Question

The nuclear DNA content of a single sperm cell in Drosophila melanogaster is approximately 0.18 picogram. What would be the expected nuclear DNA content of a primary spermatocyte in Drosophila? What would be the expected nuclear DNA content of a somatic cell (non-sex cell) in the G1 phase? What would be the expected nuclear DNA content of a somatic cell at metaphase?

Accepted Answer

Hi everyone. Let's take a look at this practice problem together due to the presence of a cell wall, psychokinesis and plant cells is significantly different from that in animal cells. Rather than forming a contract, I'll ring plant cells construct a cell plate in the middle of the cell. The list below shows the stages of cell plate formation. And then we are given one trafficking of vesicles to the division plane and their fusion to generate a tubular vesicular network to creation of the fragment past three, fusion with the parental cell wall, four recycling of excess membrane and other material from the cell plate and five deposition of callus cellulose and other cell wall components. So psychokinesis implants is different because the cell wall is semi rigid. And so that cell plate is the basis of how the two daughter cells are formed and it basically occurs from the inside out. So cell plate formation, the very first step is going to be to creation of the fragment plast. Now, what is the fragment plast? Well, that is an array of micro tubules that will support the formation of the cell plate. So the very first step in our sequence is going to be two knowing that we can eliminate both A and C. Since they list a different step being first, after the fragment plast, you're gonna have trafficking of vesicles to the division plane. So one is gonna be vesicles movement. And so the vesicles are going to move towards the middle to begin to carry necessary components that the cell plate needs in order to continue growing after one, You'll have deposition of callow cellulose and other cell wall components, which is step five. So this is going to be deposition of cell materials in order to continue growing that cell plate so thus far are sequences to 15. So after depositing cell material, the next step will be recycling of excess membrane and other material from the cell plate. So that is step forward and then that's just recycling basically of excess cell material. And then the last step is going to be the cell plate fusion. Sorry, that should be three. It should be cell plate fusion with the parental cell wall and then you get the formation of the two daughter cells. And so the sequence is 2154 and then three. So that is going to be option D. So D. Is the correct answer. Alright, everyone. I hope you found this helpful and I'll see you soon for the next practice problem.

Key Concepts

Haploid and Diploid Cells

Cell Cycle Phases

DNA Content at Different Stages

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