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Ch. 12 - DNA Organization in Chromosomes
Klug - Concepts of Genetics  12th Edition
Klug12th EditionConcepts of Genetics ISBN: 9780135564776Not the one you use?Change textbook
Chapter 12, Problem 25

Microsatellites are currently exploited as markers for paternity testing. A sample paternity test is shown in the following table in which ten microsatellite markers were used to test samples from a mother, her child, and an alleged father. The name of the microsatellite locus is given in the left-hand column, and the genotype of each individual is recorded as the number of repeats he or she carries at that locus. For example, at locus D9S302, the mother carries 30 repeats on one of her chromosomes and 31 on the other. In cases where an individual carries the same number of repeats on both chromosomes, only a single number is recorded. (Some of the numbers are followed by a decimal point, for example, 20.2, to indicate a partial repeat in addition to the complete repeats.) Assuming that these markers are inherited in a simple Mendelian fashion, can the alleged father be excluded as the source of the sperm that produced the child? Why or why not? Explain.

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Step 1: Understand the inheritance pattern of microsatellite markers. Microsatellites are inherited in a Mendelian fashion, meaning that a child inherits one allele (number of repeats) from the mother and one allele from the father at each locus. This principle will guide the analysis of the data provided in the table.
Step 2: Compare the child's genotype at each microsatellite locus with the mother's genotype. Identify which allele (number of repeats) the child inherited from the mother. This will help determine which allele must have been inherited from the father.
Step 3: Compare the child's genotype with the alleged father's genotype at each locus. For each locus, check if the allele that the child did not inherit from the mother matches one of the alleged father's alleles. If there is a mismatch at any locus, the alleged father can be excluded as the biological father.
Step 4: Pay special attention to cases where the child has an allele that neither the mother nor the alleged father possesses. This would definitively exclude the alleged father as the biological father for that locus.
Step 5: Summarize the findings across all loci. If mismatches are found at multiple loci, the alleged father can be excluded with high confidence. If all loci match, the alleged father cannot be excluded based on the data provided.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Microsatellites

Microsatellites, also known as short tandem repeats (STRs), are repetitive sequences of DNA that consist of 1-6 base pairs repeated multiple times. They are highly polymorphic, meaning they vary greatly among individuals, making them useful for genetic profiling. In paternity testing, the number of repeats at specific loci can help determine genetic relationships, as children inherit one allele from each parent.
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Mendelian Inheritance

Mendelian inheritance refers to the principles of genetic inheritance established by Gregor Mendel, which include the concepts of dominant and recessive alleles. In the context of microsatellites, it implies that alleles at a locus are inherited in a predictable manner, with one allele coming from each parent. This framework allows for the analysis of whether the alleged father can pass on the observed alleles in the child.
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Paternity Testing

Paternity testing involves comparing the genetic markers of a child with those of the mother and the alleged father to determine biological relationships. By analyzing microsatellite loci, one can identify whether the alleged father shares the necessary alleles with the child. If the child possesses an allele that the alleged father does not have, he can be excluded as the biological father.
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Related Practice
Textbook Question

An article entitled 'Nucleosome Positioning at the Replication Fork' states: 'both the 'old' randomly segregated nucleosomes as well as the 'new' assembled histone octamers rapidly position themselves (within seconds) on the newly replicated DNA strands' [Lucchini et al. (2002)]. Given this statement, how would one compare the distribution of nucleosomes and DNA in newly replicated chromatin? How could one experimentally test the distribution of nucleosomes on newly replicated chromosomes?

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Textbook Question

The human genome contains approximately 106 copies of an Alu sequence, one of the best-studied classes of short interspersed elements (SINEs), per haploid genome. Individual Alu units share a 282-nucleotide consensus sequence followed by a 3'-adenine-rich tail region [Schmid (1998)]. Given that there are approximately 3 x 109 base pairs per human haploid genome, about how many base pairs are spaced between each Alu sequence?

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Textbook Question

The following is a diagram of the general structure of the bacteriophage chromosome. Speculate on the mechanism by which it forms a closed ring upon infection of the host cell.

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Textbook Question

At the end of the short arm of human chromosome 16 (16p), several genes associated with disease are present, including thalassemia and polycystic kidney disease. When that region of chromosome 16 was sequenced, gene-coding regions were found to be very close to the telomere-associated sequences. Could there be a possible link between the location of these genes and the presence of the telomere-associated sequences? What further information concerning the disease genes would be useful in your analysis?

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Textbook Question

Spermatogenesis in mammals results in sperm that have a nucleus that is 40 times smaller than an average somatic cell. Thus, the sperm haploid genome must be packaged very tightly, yet in a way that is reversible after fertilization. This sperm-specific DNA compaction is due to a nucleosome-to-nucleoprotamine transition, where the histone-based nucleosomes are removed and replaced with arginine-rich protamine proteins that facilitate a tighter packaging of DNA. In 2013 Montellier et al. showed that replacement of the H2B protein in the nucleosomes with a testis-specific variant of H2B called TSH2B is a critical step prior to the nucleosome-to-nucleoprotamine transition. Mice lacking TSH2B retain H2B and their sperm arrest late in spermatogenesis with reduced DNA compaction. Based on these findings, would you expect that TSH2B-containing nucleosomes are more or less stable than H2B-containing nucleosomes? Explain your reasoning.

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