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Ch. 10 - Eukaryotic Chromosome Abnormalities and Molecular Organization
Sanders - Genetic Analysis: An Integrated Approach 3rd Edition
Sanders3rd EditionGenetic Analysis: An Integrated ApproachISBN: 9780135564172Not the one you use?Change textbook
Chapter 10, Problem 22c

Two experimental varieties of strawberry are produced by crossing a hexaploid line that contains 48 chromosomes and a tetraploid line that contains 32 chromosomes. Experimental variety 1 contains 40 chromosomes, and experimental variety 2 contains 56 chromosomes.
How many chromosomes from the tetraploid lines are contributed to experimental variety 1? To experimental variety 2?

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1
Step 1: Understand the ploidy levels and chromosome numbers of the parent lines. The hexaploid line has 48 chromosomes, meaning it has 6 sets of chromosomes (48 ÷ 6 = 8 chromosomes per set). The tetraploid line has 32 chromosomes, meaning it has 4 sets of chromosomes (32 ÷ 4 = 8 chromosomes per set). Both lines share the same base chromosome number (8).
Step 2: Analyze the chromosome numbers in the experimental varieties. Experimental variety 1 has 40 chromosomes, and experimental variety 2 has 56 chromosomes. These numbers are derived from contributions by both the hexaploid and tetraploid parent lines.
Step 3: Determine the contribution from the hexaploid line. Since the hexaploid line contributes chromosomes in multiples of 8 (its base chromosome number), calculate how many sets of chromosomes it could contribute to each experimental variety. For variety 1 (40 chromosomes), the hexaploid line could contribute 24 chromosomes (3 sets of 8). For variety 2 (56 chromosomes), the hexaploid line could contribute 48 chromosomes (6 sets of 8).
Step 4: Calculate the contribution from the tetraploid line. Subtract the hexaploid contribution from the total chromosome number in each experimental variety. For variety 1: 40 - 24 = 16 chromosomes from the tetraploid line. For variety 2: 56 - 48 = 8 chromosomes from the tetraploid line.
Step 5: Verify the results. Ensure that the contributions from both parent lines add up to the total chromosome numbers in each experimental variety. For variety 1: 24 (hexaploid) + 16 (tetraploid) = 40 chromosomes. For variety 2: 48 (hexaploid) + 8 (tetraploid) = 56 chromosomes. This confirms the calculations are correct.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Polyploidy

Polyploidy refers to the condition of having more than two complete sets of chromosomes. In this case, the hexaploid line has six sets (48 chromosomes) and the tetraploid line has four sets (32 chromosomes). Understanding polyploidy is essential for analyzing the genetic contributions of different parent lines in hybrid offspring.
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Autopolyploidy

Chromosome Contribution in Hybridization

In hybridization, the offspring inherit a combination of chromosomes from both parent lines. The total number of chromosomes in the hybrids can be calculated by adding the contributions from each parent. This concept is crucial for determining how many chromosomes from the tetraploid line are present in the experimental varieties.
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Chromosome Structure

Chromosome Count Calculation

Calculating the chromosome count involves understanding how many chromosomes each parent contributes to the offspring. For experimental variety 1 (40 chromosomes) and variety 2 (56 chromosomes), we can set up equations based on the known contributions from the hexaploid and tetraploid lines to find the specific contributions from the tetraploid line.
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Related Practice
Textbook Question

In Drosophila, seven partial deletions (1 to 7) shown as gaps in the following diagram have been mapped on a chromosome. This region of the chromosome contains genes that express seven recessive mutant phenotypes, identified in the following table as a through g. A researcher wants to determine the location and order of genes on the chromosome, so he sets up a series of crosses in which flies homozygous for a mutant allele are crossed with flies homozygous for a partial deletion. The progeny are scored to determine whether they have the mutant phenotype ('m' in the table) or the wild-type phenotype ('+' in the table). Use the partial deletion map and the table of progeny phenotypes to determine the order of genes on the chromosome.

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Textbook Question

Two experimental varieties of strawberry are produced by crossing a hexaploid line that contains 48 chromosomes and a tetraploid line that contains 32 chromosomes. Experimental variety 1 contains 40 chromosomes, and experimental variety 2 contains 56 chromosomes.

Do you expect both experimental lines to be fertile? Why or why not?

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Textbook Question

Two experimental varieties of strawberry are produced by crossing a hexaploid line that contains 48 chromosomes and a tetraploid line that contains 32 chromosomes. Experimental variety 1 contains 40 chromosomes, and experimental variety 2 contains 56 chromosomes.

How many chromosomes from the hexaploid line are contributed to experimental variety 1? To experimental variety 2?

635
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Textbook Question

In the tomato, Solanum esculentum, tall (D−)(D−) is dominant to dwarf (dd) plant height, smooth fruit (P−) is dominant to peach fruit (pp), and round fruit shape (O−) is dominant to oblate fruit shape (oo). These three genes are linked on chromosome 1 of tomato in the order dwarf–peach–oblate. There are 12 map units between dwarf and peach and 17 map units between peach and oblate. A trihybrid plant (DPO/dpo) is test-crossed to a plant that is homozygous recessive at the three loci (dpo/dpo). The accompanying table shows the progeny plants. Identify the mechanism responsible for the resulting data that do not agree with the established genetic map.

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Textbook Question

A boy with Down syndrome (trisomy 21) has 46 chromosomes. His parents and his two older sisters have a normal phenotype, but each has 45 chromosomes.

Explain how this is possible.

497
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Textbook Question

A boy with Down syndrome (trisomy 21) has 46 chromosomes. His parents and his two older sisters have a normal phenotype, but each has 45 chromosomes.

How many chromosomes do you expect to see in karyotypes of the parents?

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