Table of contents

1. Matter and Measurements4h 31m
2. Atoms and the Periodic Table5h 23m
3. Ionic Compounds2h 18m
4. Molecular Compounds2h 18m
5. Classification & Balancing of Chemical Reactions3h 17m
6. Chemical Reactions & Quantities2h 27m
7. Energy, Rate and Equilibrium3h 46m
8. Gases, Liquids and Solids3h 25m
9. Solutions4h 10m
10. Acids and Bases3h 29m
11. Nuclear Chemistry56m
BONUS: Lab Techniques and Procedures1h 38m
BONUS: Mathematical Operations and Functions47m
12. Introduction to Organic Chemistry1h 34m
13. Alkenes, Alkynes, and Aromatic Compounds2h 12m
14. Compounds with Oxygen or Sulfur1h 6m
15. Aldehydes and Ketones1h 1m
16. Carboxylic Acids and Their Derivatives1h 11m
17. Amines39m
18. Amino Acids and Proteins1h 51m
19. Enzymes1h 37m
20. Carbohydrates1h 41m
21. The Generation of Biochemical Energy2h 8m
22. Carbohydrate Metabolism2h 22m
23. Lipids2h 26m
24. Lipid Metabolism1h 45m
25. Protein and Amino Acid Metabolism1h 37m
26. Nucleic Acids and Protein Synthesis2h 54m

16. Carboxylic Acids and Their Derivatives

Carboxylic Acid Reactions

GOB Chemistry

16. Carboxylic Acids and Their Derivatives

Carboxylic Acid Reactions

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2:01 minutes

Problem 9a

Textbook Question

Write the balanced chemical equation for the dissociation of each of the following carboxylic acids in water:
a. pentanoic acid

Verified step by step guidance

Identify the chemical formula for pentanoic acid. Pentanoic acid is a carboxylic acid with the molecular formula C5H10O2. Its structure includes a carboxyl group (-COOH) attached to a pentane chain.

Understand the dissociation process of carboxylic acids in water. Carboxylic acids dissociate by donating a proton (H⁺) from the carboxyl group to water, forming a hydronium ion (H₃O⁺) and the conjugate base of the acid.

Write the general dissociation equation for a carboxylic acid (R-COOH) in water: R-COOH + H₂O → R-COO⁻ + H₃O⁺. Here, R represents the alkyl group attached to the carboxyl group.

Substitute the specific structure of pentanoic acid into the general equation. The alkyl group (R) in pentanoic acid is C4H9, so the dissociation equation becomes: C4H9-COOH + H₂O → C4H9-COO⁻ + H₃O⁺.

Verify that the equation is balanced. Ensure that the number of atoms and charges are equal on both sides of the equation. In this case, the equation is already balanced as written.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Carboxylic Acids

Carboxylic acids are organic compounds characterized by the presence of one or more carboxyl groups (-COOH). They are known for their acidic properties due to the ability of the carboxyl group to donate a proton (H+) in solution. This makes them important in various chemical reactions, including dissociation in water, where they release protons and form carboxylate ions.

Dissociation in Water

Dissociation in water refers to the process by which a compound separates into its constituent ions when dissolved in water. For carboxylic acids, this involves the release of a proton (H+) from the carboxyl group, resulting in the formation of a negatively charged carboxylate ion. Understanding this process is crucial for writing balanced chemical equations that accurately represent the behavior of acids in aqueous solutions.

Balanced Chemical Equation

A balanced chemical equation represents a chemical reaction with equal numbers of each type of atom on both sides of the equation. Balancing is essential to comply with the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction. In the context of carboxylic acids, writing a balanced equation for their dissociation involves ensuring that the number of atoms of each element is the same before and after the reaction.

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