Using condensed structural formulas, or line-angle formulas if cyclic, write the balanced chemical equations for the (1) reaction of each of the following amines with water and (2) neutralization with HCl:
c. aniline

Question

Using condensed structural formulas, or line-angle formulas if cyclic, write the balanced chemical equations for the (1) reaction of each of the following amines with water and (2) neutralization with HCl:
c. aniline

c. aniline

Accepted Answer

Welcome back, everyone provide two separate balanced chemical equations for the reactions of cyclo hexamine with water and H I or basically hydrotic acid. So let's begin with the first part of the problem. And of course, we want to begin by drawing the structure of cyclohexane amine. As the name suggests, we're going to have a cyclic structure, a six membered ring, it says cyclohexane, right? And now that we have drawn a six member ring because it's cyclohexane amine, we simply want to attach an amino group to the six membered ring. So we have drawn the structure of cyclohexane amine and according to the problem, it reacts with water. So what do we have? Well, we are observing a reaction between an amine which is considered a weak base and water. Such reaction is simply a hydrolysis reaction in which we are observing an acid base reaction. So if the amine is a base, right, that's because *** has a long pair of electrons, then water must be an acid. In this case, it must be a proton donor. This reaction must be reversible, right? And the reason why it's reversible is simply because we are using a weak base. Now, what products should we get? Bases are protein acceptors. So, nitrogen is going to accept a protein from water to form an additional nitrogen hydrogen bond. So the long pair of electrons is going to be used in the formation of an additional nitrogen hydrogen bond. This gives us NH three and now nitrogen with four bonds. Well, it has a formal positive charge since water is a proton donor, it loses one hygiene and it becomes hydroxide, hydroxide has a negative charge. And we have the products, the reaction is balanced, we simply have a proton transfer. So it's a 1 to 1 ratio. There's no need to balance it right. There are no coefficients involved. They are all 1 to 1. Now, for the second reaction, the starting material is the same. However, in this case, instead of using water, we are not performing hydrolysis, we are using a strong acid hydrotic acid because it is a strong acid. And it doesn't represent a hydrolysis reaction. We're going to use a forward arrow, not reversible arrows and illustrate another acid base reaction. Because in this case, we have a strong acid H I and a weak base. Similarly to the previous problem or the previous part of this problem, we're just going to illustrate the proton transfer from the acid to the base. So we're going to get the same cion what NH three plus we have our ammonium salt plus the iodide anion because H I loses H and becomes I with a negative charge. And once again, we don't need to balance it because we simply have a product transfer and this is a 1 to 1 reaction. Thank you for watching.

Using condensed structural formulas, or line-angle formulas if cyclic, write the balanced chemical equations for the (1) reaction of each of the following amines with water and (2) neutralization with HCl:
c. aniline

Verified video answer for a similar problem:

Key Concepts

Condensed Structural Formulas

Acid-Base Reactions

Neutralization Reactions

Using condensed structural formulas, or line-angle formulas if cyclic, write the balanced chemical equations for the (1) reaction of each of the following amines with water and (2) neutralization with HCl:c. aniline

Verified video answer for a similar problem:

Key Concepts

Condensed Structural Formulas

Acid-Base Reactions

Neutralization Reactions

Using condensed structural formulas, or line-angle formulas if cyclic, write the balanced chemical equations for the (1) reaction of each of the following amines with water and (2) neutralization with HCl:
c. aniline