Propane gas, C₃H₈, undergoes combustion with oxygen gas to produc...

Question

Propane gas, C₃H₈, undergoes combustion with oxygen gas to produce carbon dioxide and water gases. Propane has a density of 2.02 g/L at room temperature. (7.4, 7.8)a. Write the balanced chemical equation.

Accepted Answer

Hey, everyone. We're told that liquid isophane with the formula of C five H 12 is one of the components of a typical gasoline mixture. It combusts with oxygen gas to form gaseous carbon dioxide and gaseous water show the balanced chemical equation. First, let's go ahead and write out our components here. So we know that we have liquid isophane. So the formula will be C five H 12 and we will denote that it's a liquid and we have a keyword wid which implies that this will be a plus sign. So we have liquid isophane plus our oxygen gas, which we know to have a formula of +02. Next, we were told that we form gaseous carbon dioxide and gaseous water. So the term form tells us that we have a forward sign and that the next components will be our products. So we are forming gases, carbon dioxide. So we know this has the formula of CO2 and we will denote that it's a gas. And we have the term end here which tells us that this will be a plus sign. So we have carbon dioxide plus water, which has a formula of h2o and this is going to be in its gaseous state as well. So these will be our main components for our chemical equation. Now, let's go ahead and balance this out in order to do so, we need to determine the number of atoms on both our reactant side and our product side. So for each element, let's go ahead and calculate for carbon, we can see that we have five of carbon. Next, looking at our hydrogen, we have 12 of hydrogen looking at our oxygen, we have two of oxygen. Now, let's go ahead and do the same four hour product side. For our product side, we have one of carbon for our hydrogen, we have two of hydrogen and for our oxygen, we have three of oxygen. First, let's go ahead and balance out our carbons. If we add a coefficient of five prior to our carbon dioxide, we then end up with five of carbon and 11 of oxygen. Now let's go ahead and take a look at our hydrogen. We can balance out our hydrogen by adding a coefficient of six prior to our water. Once we do that, we end up with 12 of hydrogen and we end up with 16 of oxygen. Now, all we have to do is balance out our oxygen in our reactant side. If we add a coefficient of eight prior to our oxygen, we end up with 16 of oxygen. Looking at our chemical equation, it looks like everything is balanced out and this will be our final answer. Now, I hope this made sense and let us know if you have any questions.

Propane gas, C₃H₈, undergoes combustion with oxygen gas to produce carbon dioxide and water gases. Propane has a density of 2.02 g/L at room temperature. (7.4, 7.8)a. Write the balanced chemical equation.

Key Concepts

Balanced Chemical Equation

Combustion Reaction

Stoichiometry

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