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Multiple Choice
Which of the following compounds will have the highest boiling point?
A
0.10 M sucrose
B
0.10 M AgCl
C
0.25 M NH4NO3
D
0.45 M pure water
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Verified step by step guidance
1
Understand that boiling point elevation is a colligative property, which means it depends on the number of solute particles in a solution, not their identity.
Identify the van't Hoff factor (i) for each compound: Sucrose (C12H22O11) is a non-electrolyte, so i = 1. AgCl is a sparingly soluble salt, but if it were fully dissolved, i = 2. NH4NO3 is a strong electrolyte, so i = 2. Pure water has no solute, so i = 0.
Calculate the effective concentration of particles for each solution by multiplying the molarity by the van't Hoff factor: For sucrose, it's 0.10 M * 1 = 0.10 M. For AgCl, it's 0.10 M * 2 = 0.20 M. For NH4NO3, it's 0.25 M * 2 = 0.50 M. Pure water remains 0 M.
Compare the effective concentrations: The solution with the highest effective concentration of particles will have the highest boiling point.
Conclude that the 0.25 M NH4NO3 solution has the highest boiling point due to its highest effective concentration of solute particles (0.50 M).