Determine the following: a. The molarity of a solution with 0.5 moles of glucose per liter of water. b. The concentration (in weight/volume percent) of a solution that contains 20 grams of sodium chloride per liter of water. c. The concentration (in mg/dL) of a solution with 1 gram of lactic acid per 100 mL of solution. d. The molarity of a solution with 1 mmol of solute in 1 L of water.
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For part (a), recall that molarity (M) is defined as the number of moles of solute divided by the volume of the solution in liters. Use the formula: \(M = \frac{\text{moles of solute}}{\text{volume of solution in liters}}\). Here, you have 0.5 moles of glucose per liter, so substitute these values into the formula.
For part (b), weight/volume percent (% w/v) is calculated as the mass of solute in grams divided by the volume of solution in milliliters, multiplied by 100. Use the formula: \(\% \text{w/v} = \left( \frac{\text{grams of solute}}{\text{mL of solution}} \right) \times 100\). Convert 1 liter to milliliters (1000 mL) and substitute the given values.
For part (c), concentration in mg/dL means milligrams of solute per deciliter of solution. First, convert 1 gram of lactic acid to milligrams (1 g = 1000 mg). Then, note that 100 mL equals 1 deciliter (dL). Use the formula: \(\text{mg/dL} = \frac{\text{mg of solute}}{\text{dL of solution}}\) and substitute the values.
For part (d), molarity is again moles of solute per liter of solution. Here, 1 mmol (millimole) is equal to 0.001 moles. Use the formula: \(M = \frac{\text{moles of solute}}{\text{volume in liters}}\). Since the volume is 1 L, substitute the values accordingly.
After setting up each formula with the correct units and values, perform the arithmetic operations to find the numerical concentrations for each part.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Molarity
Molarity is a measure of the concentration of a solute in a solution, expressed as moles of solute per liter of solution. It is commonly used in chemistry to quantify how much of a substance is dissolved in a given volume, facilitating stoichiometric calculations in reactions.
Weight/Volume Percent Concentration
Weight/volume percent (% w/v) expresses the concentration of a solution as grams of solute per 100 milliliters of solution. It is useful for describing solutions where the solute is a solid dissolved in a liquid, providing a straightforward way to communicate concentration in practical lab settings.
Understanding unit conversions, such as milligrams per deciliter (mg/dL) or millimoles to moles, is essential for accurately interpreting and calculating solution concentrations. These conversions allow comparison and communication of concentrations across different measurement systems.