Show how you would accomplish the following synthetic conversions by adding an organolithium reagent to an acid. (d) phenylacetic acid → 3,3-dimethyl-1-phenylbutan-2-one
Verified step by step guidance
1
Step 1: Begin by understanding the target transformation. The goal is to convert phenylacetic acid (C₆H₅CH₂COOH) into 3,3-dimethyl-1-phenylbutan-2-one. This involves adding a new carbon chain and introducing a ketone functional group.
Step 2: Convert phenylacetic acid into a more reactive intermediate. Use a reagent like thionyl chloride (SOCl₂) to transform the carboxylic acid group (-COOH) into an acid chloride (-COCl). This step increases the electrophilicity of the carbonyl carbon, making it more reactive toward nucleophiles.
Step 3: Prepare the organolithium reagent. To introduce the 3,3-dimethyl group, synthesize tert-butyllithium ((CH₃)₃CLi) by reacting tert-butyl bromide ((CH₃)₃CBr) with lithium metal. This organolithium reagent will act as a nucleophile in the next step.
Step 4: Perform the nucleophilic addition. React the acid chloride (C₆H₅CH₂COCl) with tert-butyllithium ((CH₃)₃CLi). The organolithium reagent will attack the carbonyl carbon of the acid chloride, forming a tetrahedral intermediate. This intermediate will collapse, expelling the chloride ion (Cl⁻) and forming a ketone.
Step 5: Verify the structure of the product. The final compound, 3,3-dimethyl-1-phenylbutan-2-one, should have the phenyl group (C₆H₅) attached to the 1-position, a ketone group at the 2-position, and two methyl groups at the 3-position. Ensure the reaction conditions are optimized to achieve the desired product.
Verified video answer for a similar problem:
This video solution was recommended by our tutors as helpful for the problem above
Video duration:
6m
Play a video:
0 Comments
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Organolithium Reagents
Organolithium reagents are highly reactive compounds containing a carbon-lithium bond. They act as strong nucleophiles in organic synthesis, allowing for the formation of carbon-carbon bonds. In the context of the question, they can be used to add alkyl groups to carbonyl compounds, facilitating the transformation of phenylacetic acid into more complex structures.
Acid-base reactions are fundamental chemical processes where an acid donates a proton (H+) and a base accepts it. In organic synthesis, the reactivity of acids can be exploited to generate reactive intermediates. When phenylacetic acid reacts with an organolithium reagent, it can deprotonate, leading to the formation of a carbanion that can further react with electrophiles to create desired products.
Carbonyl chemistry involves the study of compounds containing a carbonyl group (C=O), which is a key functional group in organic molecules. Carbonyl compounds, such as ketones and aldehydes, are pivotal in synthetic transformations. In this case, the reaction of the carbanion generated from phenylacetic acid with a suitable electrophile can lead to the formation of the target ketone, 3,3-dimethyl-1-phenylbutan-2-one.