Draw condensed structures for the compounds represented by the...

Question

Draw condensed structures for the compounds represented by the following models (black = C, gray = H, red = O, blue = N, and green = Cl):

c.

d.

Accepted Answer

Hi, everybody and welcome back. Here's our next problem, provide the mixed condensed structures for the molecules that are represented by the models below. Legend, gray is carbon white, is hydrogen, red, is oxygen and green is nitrogen. We have two different models here. They're ball and stick models. Um They're a little bit tricky, especially with these branched chains that we have because it's a little tricky to see the arrangements in space because we're kind of on top of each other. So I know I had to stare at this for quite some time, especially at molecule number one. So let's just take it slowly and look and see how these are connected to each other. So we're going to draw a mixed condensed structure as its name indicates, we start with the notion of a condensed structure. So our main chain is written in the form of a condensed structure essentially, but we show the bonds to the substituents rather than indicating them in parentheses. So shall we show the bonds to substituent? So not parentheses, and we show the types of bonds even in the main chain. So whether there's triple or double bonds, so it's just a little bit more informative than a plain old condensed structure or a little easier to read. I think. So, let's look at molecule number one, let's look for a main chain. So the easiest to see in the middle, we have a gray ball with two lines to a red ball. So that red ball is oxygen. So we have AC O double bond and then bonded to that carbon, carbon, we have a green ball. So nitrogen with just one hydrogen and then there's chains on either side, the right side is a little less cluttered, a little less complicated. So we'll start with that. So we're going to start by writing, we have AC O carbon bond. So we'll write the letter C and then draw two lines going up from it to an O. So there's our carbon bond. Again, we show the bond to the substituent there that carbon is bonded to a nitrogen. So write n next to the sea, the nitrogen is one hydrogen. So write NH now the chain going off to the right, we'll highlight that in blue from the nitro, we have a bond to a carbon and that's ach two. We can see there then another bond to a second carbon which is CH two and to a third carbon, which is CH three. So a basic propol group, there are no substituents. So we'll write CH two CH two CH three. Now we just need to deal with the left and this one's a little trickier. So let's look for our chain here from the carbonyl carbon. We've got a bond to another carbon. That carbon is a methyl substituent. So that's not our main chain. They never barn to us. Third or second carbon, excuse me. And this second carbon has two methyl groups attached. So we just consider one of them the end of the chain. So let's go to the one that's kind of projecting outwards and three no D notions, it would be kind of coming up out of the plane of the screen towards us. So we have a three carbon chain, a prop will chain coming from that carbon carbon and then two methyl substituents. So I highlight the bonds of the substituents in red. So from the first carbon out from the carbon carbon, there's a bond to a methyl group. And then again, on that second carbon, one of the, it looks like it has two methyl groups, one will call part of the main chain and then one will be a methyl substituent. So the way we write that, so working to the left kind of backwards from the carbon carbon. We've got ach that as a methyl substituent. So I draw line down from the C and write CH three and then we've got another C and that has a, another CH three that we call part of the main chain. And then we'll draw a line up from that second carbon and draw CH three other methyl group. So for number one, our final condensed structure or mixed condensed structure, we should say is CH three ch, the line from the C and then CH three, then CH with a line from the C saying CH three and C double bonded to O nhch two CH two CH three. So there's our mix condensed structure there. Then for number two, this is fortunately a little more straightforward here, we have in our main chain, we've got a carbon CH three and then we've got that's fed to a second carbon. So ch that carbon has a methyl substituent indicate with a red bond. Then we've got CH two C two and then at say choose B to a Carmen that carbon has no hydrogens, but it has three lines to a red ball for nitrogen, it's got a triple bond to nitrogen. At the end there, the nitrogen has no hydrogens. So for our Mexican in structure on the main chain, we'll write that all condensed. So we've got CH three and CH, we draw a line up from AC and write CH three. Then we have CH two CH two lastly see, and then we draw three lines for a triple wand. And so again, our mi mix condense structure there is CH three CH with a line from the C going up to CH three CH two CH two C triple bond N. So that would be our Mexican in structure four molecule. Number two. Hope to see you in the next video.

Draw condensed structures for the compounds represented by the following models (black = C, gray = H, red = O, blue = N, and green = Cl):
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d. <IMAGE>

Key Concepts

Condensed Structures

Functional Groups

Molecular Geometry

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