Open Question
Provide the mechanism for the reaction between toluene diisocyanate and butane-2,3-diol.
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36. Synthetic Polymers
Step-Growth Polymers: Polyurethane Mechanism
Multiple Choice
Determine the monomer created from the reaction between toluene diisocyanate and ethylene diol.
A
B
C
D
0 Comments
Verified step by step guidance1
Identify the functional groups in the reactants: Toluene diisocyanate contains two isocyanate groups (\( \text{NCO} \)), and ethylene diol contains two hydroxyl groups (\( \text{OH} \)).
Understand the reaction mechanism: The isocyanate group reacts with the hydroxyl group to form a urethane linkage. This involves the nucleophilic attack of the hydroxyl oxygen on the carbon of the isocyanate group, forming a carbamate (urethane) linkage.
Visualize the structure of the monomer: The reaction between one isocyanate group and one hydroxyl group forms a urethane linkage, \( \text{NHCOO} \). Since both reactants are di-functional, the reaction will form a linear monomer with urethane linkages at both ends.
Consider the repeating unit: The monomer formed will have a structure where the urethane linkage connects the aromatic ring of toluene diisocyanate to the ethylene chain of ethylene diol.
Analyze the images: The images provided show structures with urethane linkages, indicating the formation of a monomer with the expected urethane linkage between the aromatic ring and the ethylene chain.
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