Textbook Question
What is the major product of the reaction of 2-methyl-2-butene with each of the following reagents?
b. HI
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Ch. 6 - The Reactions of Alkenes • The Stereochemistry of Addition Reactions
Bruice8th EditionOrganic ChemistryISBN: 9780135213711
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Table of contents
- Ch. 1 - Remembering General Chemistry: Electronic Structure and Bonding (Part 1)31
- Ch. 1 - Remembering General Chemistry: Electronic Structure and Bonding (Part 2)65
- Ch. 2 - Acids and Bases: Central to Understanding Organic Chemistry84
- Ch. 3 - An Introduction to Organic Compounds:Nomenclature, Physical Properties, and Structure183
- Ch. 4 - Isomers: The Arrangement of Atoms in Space121
- Ch. 5 - Alkenes: Structure, Nomenclature, and an Introduction to Reactivity • Thermodynamics and Kinetics83
- Ch. 6 - The Reactions of Alkenes • The Stereochemistry of Addition Reactions175
- Ch. 7 - The Reactions of Alkynes • An Introduction to Multistep Synthesis119
- Ch. 8 - Delocalized Electrons: Their Effect on Stability, pKa, and the Products of a Reaction • Aromaticity and Electronic Effects: An Introduction to the Reactions of Benzene148
- Ch. 9 - Substitution and Elimination Reactions of Alkyl Halides212
- Ch. 10 - Reactions of Alcohols, Ethers, Epoxides, Amines, and Sulfur-Containing Compounds131
- Ch. 11 - Organometallic Compounds60
- Ch. 12 - Radicals90
- Ch. 13 - Mass Spectrometry; Infrared Spectroscopy; UV/Vis Spectroscopy62
- Ch. 14 - NMR Spectroscopy95
- Ch. 15 - Reactions of Carboxylic Acids and Carboxylic Acid Derivatives123
- Ch. 16 - Reactions of Aldehydes and Ketones • More Reactions of Carboxylic Acid Derivatives141
- Ch. 17 - Reactions at the Alpha-Carbon101
- Ch. 18 - Reactions of Benzene and Substituted Benzenes144
- Ch. 19 - More About Amines • Reactions of Heterocyclic Compounds49
- Ch. 20 - The Organic Chemistry of Carbohydrates80
- Ch. 21 - Amino Acids, Peptides, and Proteins57
- Ch. 22 - Catalysis in Organic Reactions and in Enzymatic Reactions35
- Ch. 23 - The Organic Chemistry of the Coenzymes—Compounds Derived from Vitamins1
- Ch. 28 - Pericyclic Reactions58
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Bruice 8th EditionCh. 6 - The Reactions of Alkenes • The Stereochemistry of Addition ReactionsProblem 57c
Bruice 8th EditionCh. 6 - The Reactions of Alkenes • The Stereochemistry of Addition ReactionsProblem 57cChapter 7, Problem 57c
Identify the electrophile and the nucleophile in each of the following reaction steps and then draw curved arrows to illustrate the bond-making and bondbreaking processes.
c. 
Verified step by step guidance1
Step 1: Identify the electrophile and nucleophile in the reaction. The electrophile is BH₃ (borane) because it has an empty p-orbital and can accept electrons. The nucleophile is CH₃CH=CH₂ (propene) because the π-electrons in the double bond can donate electrons.
Step 2: Analyze the bond-making and bond-breaking process. The π-electrons from the double bond in propene attack the boron atom in BH₃, forming a new bond between the boron and one of the carbon atoms in the double bond.
Step 3: Draw curved arrows to represent the electron movement. One curved arrow should originate from the π-electrons of the double bond and point toward the boron atom in BH₃, indicating the formation of the new bond.
Step 4: Note the regioselectivity of the reaction. In hydroboration, the boron atom typically attaches to the less substituted carbon of the double bond due to steric and electronic factors.
Step 5: The product of the reaction is CH₃CH₂CH₂BH₂, where the double bond is broken, and a single bond is formed between boron and the less substituted carbon atom. Ensure the curved arrows accurately depict the electron flow leading to this product.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Electrophiles
Electrophiles are species that accept electrons during a chemical reaction. They are typically positively charged or neutral molecules with an electron-deficient atom, making them attractive to nucleophiles. In the given reaction, borane (BH3) acts as the electrophile, as it can accept a pair of electrons from the alkene.
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Nucleophile or Electrophile
Nucleophiles
Nucleophiles are electron-rich species that donate a pair of electrons to form a chemical bond. They are usually negatively charged or neutral molecules with a lone pair of electrons. In this reaction, the alkene (CH3CH=CH2) serves as the nucleophile, providing electrons to bond with the electrophile, borane.
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Curved Arrows in Mechanisms
Curved arrows are used in organic chemistry to illustrate the movement of electrons during chemical reactions. The tail of the arrow indicates the electron source (where the electrons are coming from), while the head points to the electron destination (where the electrons are going). In this reaction, curved arrows would show the electron donation from the alkene to borane, indicating bond formation and breaking.
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Related Practice
Textbook Question
What is the major product of the reaction of 2-methyl-2-butene with each of the following reagents?
a. HBr
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Textbook Question
Which electrophilic addition reactions
d. form a five-membered ring intermediate?
1140
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Textbook Question
What is the major product of the reaction of 2-methyl-2-butene with each of the following reagents?
d. O3, −78 °C, followed by (CH3)2S
769
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Textbook Question
Identify the electrophile and the nucleophile in each of the following reaction steps and then draw curved arrows to illustrate the bond-making and bondbreaking processes.
a.
910
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Textbook Question
Identify the electrophile and the nucleophile in each of the following reaction steps and then draw curved arrows to illustrate the bond-making and bondbreaking processes.
b.
663
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