Textbook Question
Draw the structures of the products obtained from the following reaction:
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Ch. 9 - Substitution and Elimination Reactions of Alkyl Halides
Bruice8th EditionOrganic ChemistryISBN: 9780135213711
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Table of contents
- Ch. 1 - Remembering General Chemistry: Electronic Structure and Bonding (Part 1)31
- Ch. 1 - Remembering General Chemistry: Electronic Structure and Bonding (Part 2)65
- Ch. 2 - Acids and Bases: Central to Understanding Organic Chemistry84
- Ch. 3 - An Introduction to Organic Compounds:Nomenclature, Physical Properties, and Structure183
- Ch. 4 - Isomers: The Arrangement of Atoms in Space121
- Ch. 5 - Alkenes: Structure, Nomenclature, and an Introduction to Reactivity • Thermodynamics and Kinetics83
- Ch. 6 - The Reactions of Alkenes • The Stereochemistry of Addition Reactions175
- Ch. 7 - The Reactions of Alkynes • An Introduction to Multistep Synthesis119
- Ch. 8 - Delocalized Electrons: Their Effect on Stability, pKa, and the Products of a Reaction • Aromaticity and Electronic Effects: An Introduction to the Reactions of Benzene148
- Ch. 9 - Substitution and Elimination Reactions of Alkyl Halides212
- Ch. 10 - Reactions of Alcohols, Ethers, Epoxides, Amines, and Sulfur-Containing Compounds131
- Ch. 11 - Organometallic Compounds60
- Ch. 12 - Radicals90
- Ch. 13 - Mass Spectrometry; Infrared Spectroscopy; UV/Vis Spectroscopy62
- Ch. 14 - NMR Spectroscopy95
- Ch. 15 - Reactions of Carboxylic Acids and Carboxylic Acid Derivatives123
- Ch. 16 - Reactions of Aldehydes and Ketones • More Reactions of Carboxylic Acid Derivatives141
- Ch. 17 - Reactions at the Alpha-Carbon101
- Ch. 18 - Reactions of Benzene and Substituted Benzenes144
- Ch. 19 - More About Amines • Reactions of Heterocyclic Compounds49
- Ch. 20 - The Organic Chemistry of Carbohydrates80
- Ch. 21 - Amino Acids, Peptides, and Proteins57
- Ch. 22 - Catalysis in Organic Reactions and in Enzymatic Reactions35
- Ch. 23 - The Organic Chemistry of the Coenzymes—Compounds Derived from Vitamins1
- Ch. 28 - Pericyclic Reactions58
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Bruice 8th EditionCh. 9 - Substitution and Elimination Reactions of Alkyl HalidesProblem 115c
Bruice 8th EditionCh. 9 - Substitution and Elimination Reactions of Alkyl HalidesProblem 115cChapter 10, Problem 115c
Draw the products of each of the following SN2/E2 reactions. If the products can exist as stereoisomers, show which stereoisomers are formed.
c. (3S,4R)-3-bromo-4-methylhexane + CH3O−
Verified step by step guidance1
Analyze the reaction type: The problem specifies SN2/E2 reactions. SN2 (bimolecular nucleophilic substitution) and E2 (bimolecular elimination) are competing mechanisms. The choice depends on the substrate, nucleophile/base, and reaction conditions. Here, CH3O− is a strong nucleophile and a strong base, so both SN2 and E2 are possible.
Examine the substrate: The substrate is (3S,4R)-3-bromo-4-methylhexane. The bromine atom is attached to the 3rd carbon, making it a good leaving group. The stereochemistry at the 3rd carbon is S, and the 4th carbon has an R configuration with a methyl group attached.
Consider the SN2 pathway: In an SN2 reaction, the nucleophile (CH3O−) attacks the carbon bonded to the leaving group (C-3) from the opposite side, leading to an inversion of configuration at C-3. This results in a product with the 3rd carbon having an R configuration. The stereochemistry at C-4 remains unchanged (R).
Consider the E2 pathway: In an E2 reaction, the base (CH3O−) abstracts a β-hydrogen (a hydrogen on a carbon adjacent to the carbon bearing the leaving group). Here, β-hydrogens are available on both C-2 and C-4. Elimination of H from C-2 forms a double bond between C-2 and C-3, while elimination of H from C-4 forms a double bond between C-3 and C-4. The resulting alkenes can have E/Z stereoisomers depending on the spatial arrangement of substituents around the double bond.
Draw the products: For the SN2 pathway, draw the product with inversion of configuration at C-3. For the E2 pathway, draw the two possible alkenes (one with a double bond between C-2 and C-3, and the other with a double bond between C-3 and C-4), showing both E and Z stereoisomers for each alkene. Ensure the stereochemistry at C-4 remains consistent with the original R configuration.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
S<sub>N</sub>2 Mechanism
The S<sub>N</sub>2 mechanism is a type of nucleophilic substitution reaction where a nucleophile attacks an electrophile, resulting in the simultaneous displacement of a leaving group. This reaction occurs in a single concerted step, leading to inversion of configuration at the carbon center. It is favored by primary and some secondary substrates, particularly in polar aprotic solvents.
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Creating Ribonucleosides
E2 Mechanism
The E2 mechanism is a bimolecular elimination reaction where a base abstracts a proton from a β-carbon while a leaving group departs from the α-carbon, resulting in the formation of a double bond. This reaction requires a strong base and typically occurs in a single concerted step. The stereochemistry of the reaction is important, as it often leads to the formation of specific geometric isomers.
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09:36Drawing the E2 Mechanism.
Stereoisomerism
Stereoisomerism refers to the phenomenon where compounds have the same molecular formula and connectivity but differ in the spatial arrangement of atoms. In the context of S<sub>N</sub>2 and E2 reactions, stereoisomers can arise due to the configuration of chiral centers or the geometry of double bonds. Understanding stereoisomerism is crucial for predicting the products of these reactions, as different stereoisomers can exhibit distinct physical and chemical properties.
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Related Practice
Textbook Question
Explain why the rate of the reaction of 1-bromo-2-butene with ethanol is increased if silver nitrate is added to the reaction mixture.
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Textbook Question
How could you prepare the following compounds from the given starting materials?
b.
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Textbook Question
Draw the products of each of the following SN2/E2 reactions. If the products can exist as stereoisomers, show which stereoisomers are formed.
a. (3S,4S)-3-bromo-4-methylhexane + CH3O−
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Textbook Question
Two elimination products are obtained from the following E2 reaction:
a. What are the elimination products?
b. Which is formed in greater yield?
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Textbook Question
Draw the products of each of the following SN2/E2 reactions. If the products can exist as stereoisomers, show which stereoisomers are formed.
b. (3R,4R)-3-bromo-4-methylhexane + CH3O−
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