Textbook Question
What nucleophiles would form the following compounds as a result of reacting with 1-iodobutane?
h.
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Ch. 9 - Substitution and Elimination Reactions of Alkyl Halides
Bruice8th EditionOrganic ChemistryISBN: 9780135213711
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Table of contents
- Ch. 1 - Remembering General Chemistry: Electronic Structure and Bonding (Part 1)31
- Ch. 1 - Remembering General Chemistry: Electronic Structure and Bonding (Part 2)65
- Ch. 2 - Acids and Bases: Central to Understanding Organic Chemistry84
- Ch. 3 - An Introduction to Organic Compounds:Nomenclature, Physical Properties, and Structure183
- Ch. 4 - Isomers: The Arrangement of Atoms in Space121
- Ch. 5 - Alkenes: Structure, Nomenclature, and an Introduction to Reactivity • Thermodynamics and Kinetics83
- Ch. 6 - The Reactions of Alkenes • The Stereochemistry of Addition Reactions175
- Ch. 7 - The Reactions of Alkynes • An Introduction to Multistep Synthesis119
- Ch. 8 - Delocalized Electrons: Their Effect on Stability, pKa, and the Products of a Reaction • Aromaticity and Electronic Effects: An Introduction to the Reactions of Benzene148
- Ch. 9 - Substitution and Elimination Reactions of Alkyl Halides212
- Ch. 10 - Reactions of Alcohols, Ethers, Epoxides, Amines, and Sulfur-Containing Compounds131
- Ch. 11 - Organometallic Compounds60
- Ch. 12 - Radicals90
- Ch. 13 - Mass Spectrometry; Infrared Spectroscopy; UV/Vis Spectroscopy62
- Ch. 14 - NMR Spectroscopy95
- Ch. 15 - Reactions of Carboxylic Acids and Carboxylic Acid Derivatives123
- Ch. 16 - Reactions of Aldehydes and Ketones • More Reactions of Carboxylic Acid Derivatives141
- Ch. 17 - Reactions at the Alpha-Carbon101
- Ch. 18 - Reactions of Benzene and Substituted Benzenes144
- Ch. 19 - More About Amines • Reactions of Heterocyclic Compounds49
- Ch. 20 - The Organic Chemistry of Carbohydrates80
- Ch. 21 - Amino Acids, Peptides, and Proteins57
- Ch. 22 - Catalysis in Organic Reactions and in Enzymatic Reactions35
- Ch. 23 - The Organic Chemistry of the Coenzymes—Compounds Derived from Vitamins1
- Ch. 28 - Pericyclic Reactions58
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Bruice 8th EditionCh. 9 - Substitution and Elimination Reactions of Alkyl HalidesProblem 70g
Bruice 8th EditionCh. 9 - Substitution and Elimination Reactions of Alkyl HalidesProblem 70gChapter 10, Problem 70g
What nucleophiles would form the following compounds as a result of reacting with 1-iodobutane?
g. 
Verified step by step guidance1
Step 1: Analyze the given compound. The structure shows a butyl group attached to an oxygen atom, which is further connected to a carbonyl group (C=O) and a methyl group. This indicates the compound is an ester, specifically butyl acetate.
Step 2: Identify the starting material. The problem states that 1-iodobutane is the starting material. This compound is a primary alkyl halide, which is reactive in nucleophilic substitution reactions.
Step 3: Determine the nucleophile required to form the ester. To form butyl acetate, the nucleophile must provide the acetate group (CH3COO−). This suggests that the nucleophile is acetate ion (CH3COO−).
Step 4: Consider the reaction mechanism. The reaction likely proceeds via an SN2 mechanism because 1-iodobutane is a primary alkyl halide, which favors bimolecular nucleophilic substitution. The acetate ion attacks the carbon attached to the iodine atom, displacing the iodide ion.
Step 5: Summarize the reaction. The nucleophile (CH3COO−) reacts with 1-iodobutane in an SN2 reaction to form butyl acetate as the product, with iodide ion (I−) as the leaving group.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Nucleophiles
Nucleophiles are species that donate an electron pair to form a chemical bond in a reaction. They are typically negatively charged or neutral molecules with lone pairs of electrons. In the context of nucleophilic substitution reactions, such as SN2, nucleophiles attack electrophilic centers, like the carbon atom bonded to a leaving group, facilitating the substitution process.
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Nucleophilic Addition
SN2 Reaction Mechanism
The SN2 (substitution nucleophilic bimolecular) reaction is a type of nucleophilic substitution where the nucleophile attacks the electrophile from the opposite side of the leaving group, resulting in a concerted mechanism. This reaction is characterized by a single transition state and leads to inversion of configuration at the carbon center. It is favored by primary substrates, like 1-iodobutane, due to less steric hindrance.
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08:33Drawing the SN2 Mechanism
Leaving Groups
Leaving groups are atoms or groups that can depart from the parent molecule during a chemical reaction, allowing for the formation of new bonds. A good leaving group is typically stable after departure, such as iodide in the case of 1-iodobutane. The ability of a leaving group to stabilize its negative charge is crucial in determining the rate and feasibility of nucleophilic substitution reactions.
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07:22The 3 important leaving groups to know.
Related Practice
Textbook Question
What nucleophiles would form the following compounds as a result of reacting with 1-iodobutane?
e.
f.
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Textbook Question
Explain how each of the following changes affect the rate of the reaction of 1-bromobutane with ethoxide ion in DMF.
c. The alkyl halide is changed to 1-chlorobutane.
d. The alkyl halide is changed to 2-bromobutane.
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Textbook Question
What nucleophiles would form the following compounds as a result of reacting with 1-iodobutane?
a.
b.
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Textbook Question
Explain how each of the following changes affect the rate of the reaction of 1-bromobutane with ethoxide ion in DMF.
a. The concentration of both the alkyl halide and the nucleophile are tripled.
b. The solvent is changed to ethanol.
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Textbook Question
Which member in each pair in [PROBLEM 9-68] is a better leaving group?
e. I− or Br−
f. Cl− or Br−
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