How much less per year would it cost a family to operate a heat pump that has a coefficient of performance of 2.9 than an electric heater that costs $2100 to heat their home for a year? If the conversion to the heat pump costs $15,000, how long would it take the family to break even on heating costs? How much would the family save in 20 years?
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Heat Engines & PV Diagrams
Problem 83
Textbook Question
The Stirling cycle, shown in Fig. 20–27, is useful to describe some heat engines. Find the efficiency of the cycle in terms of the parameters shown, assuming an ideal monatomic gas as the working substance. The processes ab and cd are isothermal whereas bc and da are at constant volume. How does it compare to the Carnot efficiency?


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Step 1: Begin by recalling the definition of efficiency for a heat engine, which is given by η = (W_net / Q_in), where W_net is the net work done by the engine and Q_in is the heat absorbed during the cycle. For the Stirling cycle, the heat exchanges occur during the isothermal processes (ab and cd).
Step 2: Analyze the isothermal processes. During the isothermal expansion (ab), the heat absorbed by the gas is Q_ab = nRT_h ln(V_b / V_a), where T_h is the temperature of the hot reservoir, V_a and V_b are the initial and final volumes, n is the number of moles, R is the gas constant, and ln represents the natural logarithm. Similarly, during the isothermal compression (cd), the heat released is Q_cd = nRT_c ln(V_d / V_c), where T_c is the temperature of the cold reservoir.
Step 3: Evaluate the constant-volume processes. During the process bc (constant volume cooling), the gas releases heat Q_bc = nC_v(T_h - T_c), where C_v is the molar heat capacity at constant volume. During the process da (constant volume heating), the gas absorbs heat Q_da = nC_v(T_h - T_c). Note that these two processes do not contribute to the net work done, as the volume remains constant.
Step 4: Calculate the net work done (W_net). The work done during the isothermal processes is W_ab = Q_ab and W_cd = -Q_cd. Therefore, W_net = W_ab + W_cd = nRT_h ln(V_b / V_a) - nRT_c ln(V_d / V_c).
Step 5: Express the efficiency η. Substitute the values of Q_in (heat absorbed during the isothermal expansion ab) and W_net into the efficiency formula η = (W_net / Q_in). Compare this result to the Carnot efficiency η_Carnot = 1 - (T_c / T_h), which represents the maximum theoretical efficiency for a heat engine operating between two reservoirs at temperatures T_h and T_c.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Stirling Cycle
The Stirling cycle is a thermodynamic cycle that describes the operation of a Stirling engine, which is a type of heat engine. It consists of four processes: two isothermal (constant temperature) and two isochoric (constant volume). The efficiency of the Stirling cycle can be derived from the work done during these processes and the heat absorbed and released, making it a practical model for understanding heat engine performance.
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Efficiency of Heat Engines
The efficiency of a heat engine is defined as the ratio of the work output to the heat input, typically expressed as a percentage. For ideal cycles, such as the Stirling cycle, efficiency can be calculated using the temperatures of the heat reservoirs involved. This concept is crucial for comparing different heat engines, including how the Stirling cycle's efficiency relates to the theoretical maximum efficiency given by the Carnot cycle.
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Introduction to Heat Engines
Carnot Efficiency
Carnot efficiency is the maximum possible efficiency that a heat engine can achieve when operating between two thermal reservoirs at different temperatures. It is given by the formula η = 1 - (T_c/T_h), where T_c is the absolute temperature of the cold reservoir and T_h is the absolute temperature of the hot reservoir. This concept serves as a benchmark for evaluating the performance of real heat engines, including the Stirling cycle.
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The Carnot Cycle and Maximum Theoretical Efficiency
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